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pychu [463]
2 years ago
8

3Evaluate (1/2)plzzz helpppp meeee​

Mathematics
1 answer:
larisa [96]2 years ago
6 0

Answer:

0.5

Step-by-step explanation:

1/2 is one half, and if you divide 1 by 2 using long division you get 0.5

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5. 3g + 9 = 2. 3g + 15<br>Solve for G
Alik [6]
5.3g + 9 = 2.3g + 15
5.3g + 9 - 9 = 2.3g + 15 - 9
5.3g = 2.3g + 6
5.3g - 2.3g = 2.3g - 2.3g + 6
3g = 6
3g / 3 = 6 / 3
g = 2
3 0
3 years ago
Read 2 more answers
Estefani‘s house is at point E (3,-2) and Jasmin’s house is at point J (-5,3). Jasmin’s house is the Mid-point of Estefani’s hou
iren [92.7K]

The formula for midpoint is

(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})

Look at the image below to see the line segment of Estefani's (A), Jasmin's (M), and Preston's (B) houses. Keep in mind that the segment shown below is not accurate in regards to how the line segment formed by Estefani's, Jasmin's, and Preston's houses. It is simply there so you can picture the segment better.

In this case:

x_{1} =3\\x_{2} =unknown\\y_{1} =-2\\y_{2} =unknown

^^^Plug in these number into the formula given above...

(\frac{3+x}{2}, \frac{-2 + y}{2})

To find what x is (a coordinate of Preston's house) you must take the x-value part of the midpoint equation (\frac{3+x}{2}) and set it equal to the x-value of the midpoint (-5). Then you must solve for x:

\frac{3+x}{2} = -5

3 + x = -5 * 2

3 + x = -10

x = -10 - 3

x = -13

To find what y is (a coordinate of Preston's house) you must take the  y-value part of the midpoint equation(\frac{-2 + y}{2}) and set it equal to the y-value of the midpoint (3). Then you must solve for y:

\frac{-2 + y}{2} = 3

-2 + y = 3 * 2

-2 + y = 6

y = 6 + 2

y = 8

The coordinate of Preston's house is:

(-13, 8)

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0
3 years ago
Solve the formula for the indicated variable.<br> T(r+s)=rs, for r<br> (Simplify your answer.)
yaroslaw [1]

Answer:

R = \frac{-TS}{(T-S)}

Step-by-step explanation:

First, distribute all terms

T(R+S) =RS\\TR + TS =RS

Get all terms with R onto the same side

TR + TS = RS\\TR - RS = -TS

Factor out the R

R(T-S)=-TS

Divide by (T-S) to isolate R

R = \frac{-TS}{(T-S)}

5 0
3 years ago
Read 2 more answers
HELP MEE PLEASE HELP
SOVA2 [1]

Answer:

42.75

Step-by-step explanation:

area of one piece, length x width:    3 x 4 3/4

                                                                14.25

area of 3 pieces:   14.25(3)= 42.75

8 0
2 years ago
BRAINLIESSTTTT ASAP !!!!!!!!!! 20 pointssss
Mars2501 [29]
Answers:  
_____________________________________________________
   Part A)  " (3x + 4) " units  . 
_____________________________________________________
   Part B)  "The dimensions of the rectangle are:

                             " (4x + 5y) " units ;  <u>AND</u>:  " (4x − 5y)"  units."
_____________________________________________________

Explanation for  Part A):
_____________________________________________________

Since each side length of a square is the same; 
   
    Area = Length * width = L * w ;  L = w  = s = s ;

      in which:  " s = side length" ;

So, the Area of a square, "A"  = L * w = s * s = s² ;

{<u>Note</u>:  A "square" is a rectangle with 4 (four) equal sides.}.

→  Each side length, "s", of a square is equal.

Given:  s² = "(9x² + 24x + 16)" square units ;

Find "s" by factoring: "(9x² + 24x + 16)" completely:

   →  " 9x² + 24x + 16 ";

Factor by "breaking into groups" :

"(9x² + 24x + 16)"  = 

    →  "(9x² + 12x) (12x + 16)" ;
_______________________________________________________

Given:   " (9x² + 24x + 16) " ; 
_______________________________________________________
Let us start with the term:
_______________________________________________________

" (9x² + 12x) " ; 

    →  Factor out a "3x" ;  → as follows:
_______________________________________

    → " 3x (3x + 4) " ; 

Then, take the term:
_______________________________________
    → " (12x + 16) " ;

And factor out a "4" ;   →  as follows:
_______________________________________

    → " 4 (3x + 4) " 
_______________________________________
We have:

" 9x² + 24x + 16 " ;

    =  " 3x (3x + 4)  +  4(3x + 4) " ;
_______________________________________
Now, notice the term:  "(3x + 4)" ; 

We can "factor out" this term:

3x (3x + 4)  +  4(3x + 4)  = 

     →  " (3x + 4) (3x + 4) " .  → which is the fully factored form of:

                                                   " 9x² + 24x + 16 "  ; 
____________________________________________________
     →  Or; write:  "  (3x + 4) (3x + 4)" ; as:  " (3x + 4)² " .
____________________________________________________
     →  So,  "s² = 9x² + 24x + 16 " ; 

Rewrite as:  " s² = (3x + 4)² " .

     →  Solve for the "positive value of "s" ; 

     →  {since the "side length of a square" cannot be a "negative" value.}.
____________________________________________________
     →  Take the "positive square root of EACH SIDE of the equation; 
              to isolate "s" on one side of the equation; & to solve for "s" ;

     →  ⁺√(s²)  =  ⁺√[(3x + 4)²]   '

To get:

     →  s  = " (3x + 4)" units .
_______________________________________________________

Part A):  The answer is:  "(3x + 4)" units.
____________________________________________________

Explanation for Part B):

_________________________________________________________<span>

The area, "A" of a rectangle is:

    A = L * w ;  

 in which "A" is the "area" of the rectangle;
                "L" is the "length" of the rectangle; 
                "w" is the "width" of the rectangle; 
_______________________________________________________
  Given:  " A = </span>(16x² − 25y²) square units" ;  
   
       →  We are asked to find the dimensions, "L" & "w" ;
       →  by factoring the given "area" expression completely:
____________________________________________________
  → Factor:  " (16x² − 25y²) square units " completely '

Note that:  "16" and: "25" are both "perfect squares" ;
      
We can rewrite: " (16x² − 25y²) "  ;   as:

       =   " (4²x²)  −  (5²y²) " ; and further rewrite the expression:
________________________________________________________
Note:  
________________________________________________________
" (16x²) " ;  can be written as:  "(4x)² " ;

 ↔ " (4x)²  =  "(4²)(x²)" = 16x² "


Note:  The following property of exponents:

         →  (xy)ⁿ = xⁿ yⁿ ;    →  As such:  " 16x² = (4²x²) = (4x)² " . 
_______________________________________________________
Note:
_______________________________________________________

     →   " (25x²) " ;  can be written as:  " (5x)² " ; 

        ↔   "( 5x)²  =  "(5²)(x²)" = 25x² " ; 

Note:  The following property of exponents:

         →  (xy)ⁿ = xⁿ yⁿ ;    →  As such:  " 25x² = (5²x²) = (5x)² " . 
______________________________________________________

→  So, we can rewrite:  " (16x² − 25y²) " ;  

as:  " (4x)² − (5y)² " ;   
 
    → {Note:  We substitute: "(4x)² "  for "(16x²)" ; & "(5y)² "  for "(25y²)" .} . ; 
_______________________________________________________
→  We have:  " (4x)² − (5y)² " ;

→  Note that we are asked to "factor completely" ; 

→  Note that:  " x² − y² = (x + y) (x − y) " ;

      → {This property is known as the "<u>difference of squares</u>".}.

→ As such:  " (4x)² − (5y)² " = " (4x + 5y) (4x − 5y) " .
_______________________________________________________
Part B):  The answer is:  "The dimensions of the rectangle are:

                              " (4x + 5y) " units ;  AND:  " (4x − 5y)"  units."
_______________________________________________________
7 0
3 years ago
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