The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
Answer:
Step-by-step explanation:
Well 8 hundredths is also know as 0.08 if we put in in the decimal form.
I hope this helps :D
Answer: y=-5x-16
Step-by-step explanation:
Since we are given the slope and the point, we can plug in the point to solve for y-intercept.
4=-5(-4)+b [multiply]
4=20+b [subtract both sides by 20]
b=-16
Now, we know the equation is y=-5x-16.
The linear speed of one of the cars is 7.75 feet per second
The cars (seats) of a Ferris wheel are positioned 74 feet from its center.
The radius, r = 74 feet
The Ferris wheel makes 4 revolutions every 4 minutes
Number of revolutions per minute = 1
Angular speed, w = 1 rev/min
Angular speed, w = 0.10472 rad/sec
The relationship between the linear speed (v), and the angular speed (w) is:
v = wr
Substitute w = 0.10472 and r = 74 feet into the formula:
v = 0.10472 x 74
v = 7.75 feet per second
The linear speed of one of the cars is 7.75 feet per second
Learn more on linear speed here: brainly.com/question/4357151
I say its 11. Since the distance between the two points is 11.
