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3 years ago

98 POINTS AND I WILL GIVE BRAINLIES PLZZZ HELP

Mathematics

2 answers:

Sergeu [11.5K]3 years ago

8 0

Answer:

Card Color Green Blue Red

Purple Green, Purple Blue, Purple Red, Purple

Green Green, Green Blue, Green Red, Green

Step-by-step explanation:

Hope this helped! :3

OLga [1]3 years ago

5 0

Answer:It was Results of the spin

Card Color Green Blue Red

Purple Green, Purple Blue, Purple Red, Purple

Green Green, Green Blue, Green Red, Green

Step-by-step explanation:

You might be interested in

A dog breeder would like to know how many Dalmatian puppies are typically born in a litter. He conducts some research and select

podryga [215]

Answer:

c. 6.2 ± 2.626(0.21)

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 101 - 1 = 100

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 100 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.99}{2} = 0.995$ . So we have T = 2.626

The confidence interval is:

$\overline{x} \pm M$

In which $\overline{x}$ is the sample mean while M is the margin of error.

The distribution of the number of puppies born per litter was skewed left with a mean of 6.2 puppies born per litter.

This means that $\overline{x} = 6.2$

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.626\frac{2.1}{\sqrt{101}} = 2.626(0.21)$

In which s is the standard deviation of the sample and n is the size of the sample.

Thus, the confidence interval is:

$\overline{x} \pm M = 6.2 \pm 2.626(0.21)$

And the correct answer is given by option c.

5 0

3 years ago

Assume that body masses of Goldfinch birds follow a normal distribution with standard deviation equal to 0.04 oz. An ornithologi

il63 [147K]

Answer:

The formula to generate 70% confidence interval is: $[\overline{x} - 0.013, \overline{x} + 0.013]$ , in which $\overline{x}$ is the sample mean.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.7}{2} = 0.15$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.15 = 0.85$ , so Z = 1.037.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Assume that body masses of Goldfinch birds follow a normal distribution with standard deviation equal to 0.04 oz.

This means that $\sigma = 0.04$ .

Sample of 10 birds:

This means that $n = 10$ .

The margin of error is of:

$M = z\frac{\sigma}{\sqrt{n}}$

$M = 1.037\frac{0.04}{\sqrt{10}}$

$M = 0.013$

The lower end of the interval is the sample mean of $\overline{x}$ subtracted by M.

The upper end of the interval is the sample mean of $\overline{x}$ added to M.

Then, the formula to generate 70% confidence interval is: $[\overline{x} - 0.013, \overline{x} + 0.013]$ , in which $\overline{x}$ is the sample mean.

8 0

3 years ago

A rectangular fish tank has a base that is 8 inches by 7 inches. How much water will it take to fill the tank to a depth of 5 in

Blizzard [7]

V=LWH
L=8
W=7
H=5

V=8*7*5=280 in^3

you need 280 in^3 of water

5 0

3 years ago

What is the sum of the first 40 odd integers greater than zero?

marusya05 [52]

The answer you are looking for is 339

5 0

3 years ago

7.064 and expanded form

Andreas93 [3]

Answer:

seven and sixty-four thousandths

Step-by-step explanation:

in factors it would be

7 x 1

+ 0 x 0.1

+ 6 x 0.01

+ 4 x 0.001

3 0

3 years ago