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3 years ago

12x+7<-11 AND 5x-8=>40

Mathematics

2 answers:

Sladkaya [172]3 years ago

6 0

12x + 7 < -11

12x < -18

x < -1.5

5x - 8 => 40

5x => 48

x => 9.6

Andreyy893 years ago

5 0

Answer:

The values of x = [-1.5, -∞) and [9.6, ∞)

Step-by-step explanation:

Here we have to solve the given system of inequalities.

12x + 7 ≤ -11 and 5x - 8 ≥ 40

Here we have to solve for x. Let's take the first inequality and solve for x.

12x + 7 ≤ -11

Subtracting 7 from both sides,

12x + 7 - 7 ≤ -11 - 7

12x ≤ -18

Dividing both sides by 12, we get

x ≤ $\frac{-18}{12}$

We can simplify this fraction.

x $\leq \frac{-3}{2}$

x $\leq -1.5$

Now let's solve the second inequality.

5x - 8 ≥ 40

Add 8 on both sides,

5x - 8 + 8 ≥ 40 + 8

5x ≥ 48

Dividing both sides by 5, we get

x ≥ $\frac{48}{5}$

x ≥ 9.6

So, solving those inequalities, we get

x ≤ -1.5 and x ≥ 9.6

This means, the values of x = [-1.5, -∞) and [9.6, ∞)

Let's draw the solution in a number line.

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(b)

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x ----> the rainfall in centimeters

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