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dolphi86 [110]
2 years ago
5

Helppppppppp plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

Mathematics
1 answer:
mariarad [96]2 years ago
7 0

Answer:

B

Step-by-step explanation:

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Write an equation and solve for x
pashok25 [27]
X would equal 53° since a triangle has to equal 180°, 65 + 62 = 127, 180-127=53°
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2 years ago
What is 84 times one fourth
yuradex [85]

Answer:

8

Step-by-step explanation:


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3 years ago
The equation of a line is 
nadezda [96]
The answer to the question

6 0
2 years ago
Find the coordinates of the vertex of the following parabola algebraically. Write your answer as and x,y point
Likurg_2 [28]

The equation of the parabola in the vertex form is y =  (x - 3)^{2} - 5 with ( 3, -5) is the vertex of the parabola and 1 is the multiplier

In the above question, A parabolic equation is given as follows:

Y = x^2 - 6x + 4

The equation of the parabola in the vertex form is :

y = a (x - h)^{2} + k

Where a is a multiplier in the equation and (h,k) are the coordinates of the vertex

So, in order to obtain this form, we will use the method of completing square :

Y = x^2 - 6x + 4

y = x^{2} - 6x + (9 -9) + 4

y = (x - 3)^{2} + ( -9 + 4)

y =  (x - 3)^{2} - 5

where, ( 3, -5) is the vertex of the parabola and 1 is the multiplier

Hence, The equation of the parabola in the vertex form is y =  (x - 3)^{2} - 5 with ( 3, -5) is the vertex of the parabola and 1 is the multiplier

To learn more about, parabola, here

brainly.com/question/21685473

#SPJ1

8 0
1 year ago
find the gradient of the line joining (3,7) and (6,9). Hence, find the acute angle it makes with the positive x-y axis​
stiv31 [10]

Answer:

33.7 degrees

Step-by-step explanation:

As we go from (3,7) to (6,9), x increases by 3 and y increases by 2.  Thus, the gradient (slope) of the line connecting these two points is

m = rise / run = 2/3.  Using the slope-intercept formula y = mx + b, we obtain

7 = (2/3)(3) + b, or 7 = 2 + b, so we see that b = 5 and y = (2/3)x + 5.  The y-intercept is (0, 5).

Next we find the x-intercept.  We set y = (2/3)x + 5 = to 0 and solve for x:

(2/3)x = -5, or (3/2)(2/3)x = -5(3/2), or x = -15/2, so that the x-intercept is

(-15/2, 0).  This line intersects the x-axis at (-15/2, 0).

Now look at the segment of this line connecting (-15/2, 0) and (0, 5).  Here x increases by 15/2 and y increases by 5, and so the tangent of the acute angle in question is

tan Ф = 5 / (15/2) = 10 / 15 = 2/3.

Using the inverse tangent function, we get Ф = arctan 2/3, or approx.

33.7 degrees.

I believe you meant "the acute angle it makes with the positive x-axis."​

3 0
3 years ago
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