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melamori03 [73]
3 years ago
14

Mr.McNeil bought two magazines for 7.45 and one book for 14.95. If the sales tax is 6% , what is the total cost of Mr.McNeil’s p

urchase?
Mathematics
1 answer:
blagie [28]3 years ago
4 0

Answer:

total cost = $22.4 + $1.12 = $23.52

Step-by-step explanation:

Mr McNeil bought 2 magazines for $7.45 and 1 book for $14.95 . The sales tax is 6% . The total cost of Mr McNeil can be calculated as follows.

He bought 2 magazines for $7.45  .This means the sum of the prize of the 2 magazine he bought is $7.45 and the prize for the single book he bought is $14.95.  The total cost of the items he bought excluding the sales tax is the sum of the whole items he bought.

total cost excluding sales tax = $7.45 + 14.95 = $22.4

The sales tax is 5% which can be calculated as follows

5/100 × 22.4 = 112/100 = $1.12

The total cost of Mr McNeil purchase including his sales tax is

total cost = $22.4 + $1.12 = $23.52

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6 0
3 years ago
Find the vectors T, N, and B at the given point. r(t) = &lt; t^2, 2/3t^3, t &gt;, (1, 2/3 ,1)
maxonik [38]

Answer with Step-by-step explanation:

We are given that

r(t)=< t^2,\frac{2}{3}t^3,t >

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r'(t)=

\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1

T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}

Now, substitute t=1

T(1)=\frac{}{2+1}=\frac{1}{3}

T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}

T'(1)=-\frac{4}{9}+\frac{1}{3}

T'(1)=\frac{1}{9}=

\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}

N(1)=\frac{T'(1)}{\mid T'(1)\mid}

N(1)=\frac{}{\frac{2}{3}}=

N(1)=

B(1)=T(1)\times N(1)

B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}

B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})

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5 0
3 years ago
Answer please lot's of points.
Svetlanka [38]

Answer:

t≈8.0927

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We want to find when h(t) is zero ( or when it hits the ground)

0 =  -16t^2 + 128t +12

Completing the square

Subtract 12 from each side

-12  =  -16t^2 + 128t

Divide each side by -16

-12/-16  =  -16/-16t^2 + 128/-16t

3/4 = t^2 -8t

Take the coefficient of t and divide it by 8

-8/2 = -4

Then square it

(-4) ^2 = 16

Add 16 to each side

16+3/4 = t^2 -8t+16

64/4 + 3/4= (t-4)^2

67/4 = (t-4)^2

Take the square root of each side

±sqrt(67/4) =sqrt( (t-4)^2)

±1/2sqrt(67) = (t-4)

Add 4 to each side

4 ±1/2sqrt(67) = t

The approximate values for t are

t≈-0.092676

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The first is before the rocket is launched so the only valid answer is the second one

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balandron [24]

Answer:

a)219.8

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4 0
3 years ago
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Express 0.484848..... in p/q form​
cupoosta [38]
<h3>Answer:  16/33</h3>

It's in p/q form where p = 16 and q = 33.

=======================================================

Work Shown:

x = 0.484848.....

100x = 48.4848.....

I multiplied both sides by 100 to move the decimal over 2 spots. Both decimal values for x and 100x have an infinite string of "48"s repeated after the decimal point. When we subtract, those infinite strings will cancel out

100x - x = 99x

48.4848..... - 0.484848..... = 48

So after subtracting straight down, we have the new equation 99x = 48 which solves to x = 48/99

Divide both parts by the GCF 3 to fully reduce

48/3 = 16

99/3 = 33

Therefore, x = 48/99 = 16/33 = 0.484848...

I recommend using a calculator to confirm that 16/33 = 0.484848...

Side note: your calculator may round the last digit, but this is of course rounding error

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