We will get the number of possible selections, and then subtract the number less than 25 cents.
We can choose the number of dimes 5 ways 0,1,2,3 or 4.
We can choose the number of nickels 4 ways 0,1,2 or 3.
We can choose the number of quarters 3 ways 0,1, or 2.
That's 5*4*3 = 60 selections
Now we must subtract from the 60 the number of selections of coins that are less than 25 cents. These will involve only dimes and nickels.
To get a selection of coin worth less than 25 cents:
If we use no dimes, we can use 0,1,2 on all 3 nickels.
That's 4 selections less than 25 cents. (that includes the choice of No coins at all in the 60, which we must subtract).
If we use exactly 1 dime , we can use 0,1,2, or all 3 nickels.
That's the 3 combinations less than 25 cents.
And there is 1 other selection less than 25 cents, 2 dimes and no nickels.
So that's 4+3+1 = 8 selections which we must subtract from the 60.
Answer 60-8 = 52 selections of coins worth 25 cents or more.
For this case we have the following equation:

If we multiply both sides of the equation by 3 we get:
---> Multiplication Property of Equality
Applying the distributive property we have:
---> Distributive Property
Adding 1 on both sides of equality we have:

---> Addition Property of Equality
Subtracting
on both sides we have:

---> Subtraction Property of Equality
Finally, dividing by -4 on both sides we have:

---> Division Property of Equality
The correct answer is y=4x-1
Answer:

Step-by-step explanation:

To solve for the following substitute the value of x in the brackets into the above formula and solve for the value of x
<u>NB</u><u>:</u><u> </u> Absolute value of a negative number is the same number but positive.
So we have

Hope this helps you