Moles of Carbon dioxide : 0.75
<h3>Further explanation</h3>
Given
23 g C₃H₈O₃
Required
Moles of Carbon dioxide
Solution
Reaction
2C₃H₈O₃ + 7O₂ → 6CO₂ + 8H₂O
mol C₃H₈O₃ :
= mass : MW
= 23 g : 92,09382 g/mol
= 0.24975
From the equation, mol ratio of C₃H₈O₃ : 3CO₂ = 1 : 3, so mol CO₂ :
= 3/1 x mol C₃H₈O₃
= 3/1 x 0.24975
= 0.74925≈0.750 mol
A simple sugars are formed
Answer:
Explanation:
Q = m x cp x ( Final temperature - Initial temperature )
The number of moles of nitrogen gas is 1.0 mole
<u><em>calculation</em></u>
N2 is a molecule therefore;
1 molecule of N₂ = 2 atoms of N
? molecules= 1.2 x10 ²⁴atoms
<em>by cross multiplication</em>
=[( 1.2 x 10²⁴ atoms x 1 molecule) / 2 atoms] = 6 x 10²³ molecules
According to Avogadro's law 1 mole =6.02 x 10²³ molecules
? moles= 6.0 x 10²³ molecules
<em>by cross multiplication</em>
= [(6.0x 10²³ molecules x 1 mole) / 6.02 x10²³ molecules] = 1.0 mole
A lot of values are given but we must focus only on HCl.
<span>There are 215 mL (0.215 L) of 0.300 M HCl that was
completely used. We must remember the
moles is simply the product of volume and molarity, that is:</span>
number of moles = 0.215 L * 0.300 M
<span>number of moles= 0.0645 moles HCl</span>
