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Nikolay [14]
3 years ago
10

3. Oblicz stężenie procentowe 423 g roztworu zawierającego 17 g rozpuszczonego siarczanu (VI) miedzi (II). Zapisz obliczenia i o

dpowiedź. Wynik zaokrąglij.
Pomoże ktoś?
Chemistry
1 answer:
goldfiish [28.3K]3 years ago
6 0

Answer:

17 / 423 = 0.04018912529

~ 4%

proszę bardzo

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_HNO3 + _Al(OH)3
bekas [8.4K]

Answer:

Option D. 3, 1, 3, 1

Explanation:

From the question given above,

HNO₃ + Al(OH)₃ —> HOH + Al(NO₃)₃

The equation can be balance as follow:

HNO₃ + Al(OH)₃ —> HOH + Al(NO₃)₃

There are 3 atoms of N on the right side and 1 atom on the left side. It can be balance by 3 in front of HNO₃ as shown below:

3HNO₃ + Al(OH)₃ —> HOH + Al(NO₃)₃

There are a total of 6 atoms of H on the left side and 2 atoms on the right side. It can be balance by 3 in front of HOH as shown below:

3HNO₃ + Al(OH)₃ —> 3HOH + Al(NO₃)₃

Now, the equation is balanced.

Thus, the coefficients are 3, 1, 3, 1

7 0
3 years ago
(Please Help)
Marianna [84]

Answer:

B

Explanation:

Trust me I've had problems like these

6 0
3 years ago
Read 2 more answers
The chemical equation for a reaction between K2Cr2O7 and HCl is shown. K2Cr2O7 + 14HCl → 2CrCl3 + 2KCl + 3Cl2 + 7H2O
guapka [62]

<u>Answer: </u>The correct answer is Option b.

<u>Explanation:</u>

Oxidizing agent is defined as the chemical reagent which helps the other chemical compound to get oxidized and itself gets reduced. The oxidation state for these species gets reduced because they are undergoing reduction reaction.

For the given chemical equation:

K_2Cr_2O_7+14HCl\rightarrow 2CrCl_3+2KCl+3Cl_2+7H_2O

Oxidation state of Chromium is getting reduced from +6 to +3 and oxidation state of chlorine getting increased from -1 to 0.

Hence, K_2Cr_2O_7 acts like and oxidizing agent because it is itself getting reduced to CrCl_3

Therefore, the correct answer is Option b.

4 0
3 years ago
A new stable element with an atomic number of 120 and an atomic mass of 246 is created in a particle accelerator. Enough of this
deff fn [24]

Answer:

Be,Mg,Ra etc

Explanation:

It should be palced in group 2A because as it reacts with chlorine in ratio of 1:2 . It's valancy is 2 and is metal as it react with non metal donating two electrons .

one more thing it fits there orderly

3 0
3 years ago
What's the electron configuration of an N⁻³ ion
tatuchka [14]
The electronic configuration of n - 3 ion is [He] 2s2 2p3.
5 0
1 year ago
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