I think it say go rggdggy and do something with one of those other things and get a work order and get the t off and u I know I have
An alligator has has an extra eyelid that protects there eyes underwater. It's basically their own built-in goggles.
I would definitely say that the answer is
C. drought
because if they are getting 43.76 inches of rain on average, and then one year they decrease 10.31 inches of rain to 33.45 inches of rain, its a drought for sure.
First we calculate the number
of moles of Cl2, that is:
moles Cl2 = 1.5*10^10
grams/71 grams/mol = 211267605.633802817 mol = 2.1 * 10 ^ 8 mole = x <span>
So that based on stoichiometry, the number of moles of NaOH =
2x and that of H2 = x mol
mass of NaOH = 4.2*10^8 * 40 =168*10^8 grams = 1.68 * 10^6 kg
= 1.68 metric tons
<span>mass of H2 = 2.1*10^8 * 2 = 4.2*10^8 grams = 0.042 * 10^6 kg
= 0.042 metric tons.</span></span>
This question is describing two chemical equations whereby the concentration of ammonia has to be determined. The first reaction is between 25.00 mL of ammonia and 50.00 mL of 0.100-M HCl whose excess was neutralized with 21.50 mL of 0.050-M Na₂CO₃ and thus, the concentration ammonia in the cloudy solution was determined as 0.114 M.
First of all we need to go over the titration of the excess HCl with Na₂CO₃ by writing the chemical equation it takes place when they react:

Whereas the mole ratio of HCl to Na₂CO₃ is 2:1 and the volume of the HCl leftover is determined as follows:

Next, we infer that the consumed volume of HCl by the ammonia solution was:

Then, we write the chemical equation that takes place between ammonia and HCl:

Whereas the mole ratio is now 1:1, which means that the concentration of ammonia was:

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