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MrMuchimi
3 years ago
11

E = mc^2 c = ? can anyone help me find the value of c in this equation?

Mathematics
1 answer:
7nadin3 [17]3 years ago
4 0
Easy
divide both sides by m
(E/m)=c^2
sqrt both sides
\sqrt{ \frac{E}{m} } =c
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Answer:

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Step-by-step explanation:

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Assuming that s = 18,000 is a reasonable estimate for what sample size would be needed to ensure that we could estimate the true
djverab [1.8K]

Answer:

The minimum sample size required is 71.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The margin of error for this interval is:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

It is provided that the population standard deviation <em>σ</em> can be estimated by the sample standard deviation <em>s</em>.

The given information is:

<em>s</em> = 18000,

Margin of error = $4200.

Confidence level = 95%

The <em>z</em>-value for 95% confidence level is,

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a <em>z</em>-table for the critical value.

Compute the sample size required as follows:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

      n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}

         =[\frac{18000\times 1.96}{4200}]^{2}

         =70.56\\\approx71

Thus, the minimum sample size required is 71.

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