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jeka94
3 years ago
11

What is the value of x? 750 37°

Mathematics
1 answer:
RSB [31]3 years ago
3 0
Whats the problem? i cant solve it w/o the problem doll
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Jack wants to fill a rectangular box with sand. The length of the sand box is 3 feet, width is 6 inches, and height is 2.4 inche
Aleksandr-060686 [28]
Jack would need to buy 2 bags of sand.
To find the answer you first have to find the volume of the rectangular box which can be found using the formula length times width times height (remember that the numbers have to have the same unit so it would look like 3 times .5 times .2 if you convert them all the feet). the volume of the box is equal to .3
Then you could set the volume of the box equal to .15x to find how many boxes he would need. The formula would be .15x=.3
Divide by .15 to get x alone and you get 2 for the answer.
3 0
3 years ago
Read 2 more answers
Help asap plz I can’t fail this test again
amm1812

Answer:

glide reflection

Step-by-step explanation:

4 0
3 years ago
A statistician chooses 27 randomly selected dates, and when examining the occupancy records of a particular motel for those date
Anni [7]

Answer:

Confidence interval variance [21.297 ; 64.493]

Confidence interval standard deviation;

4.615, 8.031

Step-by-step explanation:

Given :

Variance, s² = 34.34

Standard deviation, s = 5.86

Sample size, n = 27

Degree of freedom, df = 27 - 1 = 26

Using the relation for the confidence interval :

[s²(n - 1) / X²α/2, n-1] ; [s²(n - 1) / X²1-α/2, n-1]

From the chi distribition table :

X²α/2, n-1 = 41.923 ; X²1-α/2, n-1 = 13.844

Hence,

[34.34*26 / 41.923] ; [34.34*26 / 13.844]

[21.297 ; 64.493]

The 95% confidence interval for the population variance is :

21.297 < σ² < 64.493

Standard deviation is the square root of variance, hence,

The 95% confidence interval for the population standard deviation is :

4.615 < σ < 8.031

3 0
3 years ago
Which are not functions select all that apply
Olegator [25]

Answer:

is it asking for linear functions

5 0
3 years ago
Consider a uniform distribution from aequals4 to bequals29. ​(a) Find the probability that x lies between 7 and 27. ​(b) Find th
weeeeeb [17]

Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

P(c \leq x \leq d) = \frac{d - c}{b - a}

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So c = 7, d = 27

P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8

80% probability that x lies between 7 and 27.

​(b) Find the probability that x lies between 6 and 13. ​

So c = 6, d = 13

P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

​So c = 9, d = 20

P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So c = 11, d = 18

P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28

28% probability that x lies between 11 and 18.

3 0
3 years ago
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