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PIT_PIT [208]
2 years ago
10

In a right triangle, if sin 0 = 8/17 what is cos 0 explain?

Mathematics
1 answer:
Oliga [24]2 years ago
3 0

Answer:

We have sin² x + cos² x =1 for all real x.

Therefore, sin² x = 1 – cos² x = 1 – (8/17)² = 1 – 64/289 = 225/289 = (15/17)².

However, remember that if x² = a², then x can be +a or –a.

Therefore, sin x can be either –15/17 or +15/17.

Everyone but Anirban so far has forgotten the negative solution.

Step-by-step explanation:

Given that sinθ=817 and cosθ<0 , we have: cosθ=−√1−sin2θ. cosθ=−√1−(817)2. cosθ=−√1−64289.

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The complete factorisation of the polynomial given; x³ + 2x² + 4x + 8 as in the task content can be factorised and determined as; Choice D; (x+2)(x+2i)(x-2i).

<h3>What is the complete factorisation of the given polynomial; x³ + 2x² + 4x+8?</h3>

It follows from the given task content that the polynomial whose factors are to be determined by means of factorisation is; x³ + 2x² + 4x+8.

It follows from observation that one of the zeros of the polynomial expression is at; x = -2.

Consequently, one of the factors of the polynomial in discuss is; (x+2).

x³ + 2x² + 4x+8 = (x+2) (x² - 4i²)

= (x+2)(x+2i)(x-2i)

Consequently, it follows that the complete factorisation of the polynomial is; (x+2)(x+2i)(x-2i).

Read more on polynomial factorisation;

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