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PIT_PIT [208]
2 years ago
10

In a right triangle, if sin 0 = 8/17 what is cos 0 explain?

Mathematics
1 answer:
Oliga [24]2 years ago
3 0

Answer:

We have sin² x + cos² x =1 for all real x.

Therefore, sin² x = 1 – cos² x = 1 – (8/17)² = 1 – 64/289 = 225/289 = (15/17)².

However, remember that if x² = a², then x can be +a or –a.

Therefore, sin x can be either –15/17 or +15/17.

Everyone but Anirban so far has forgotten the negative solution.

Step-by-step explanation:

Given that sinθ=817 and cosθ<0 , we have: cosθ=−√1−sin2θ. cosθ=−√1−(817)2. cosθ=−√1−64289.

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1. Find value of x and measure of each angle.
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the value of (5x+70) is

\frac{93}{2}

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Jimmy is selling used books at a yard sale. A customer buys 9 books at a cost of $0.75 each and pays with a $20.00 bill. Jimmy m
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= 13.25 dollars

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Can someone help me with this please!! I’ll give brainliest plus free points
IRINA_888 [86]

Answer:

The answer to your question is:  x₁ = 9     ;   x₂ = -2, third option

Step-by-step explanation:

The excluded values are those that make the denominator equal to zero.

To find the excluded values, just factor the denominator and equal to zero to find the roots.

Process

                                                               

                            x² - 7x - 18

- Find to numbers that added gives -7 and multiply -18.

- These numbers are -9 and + 2, because

           -9 + 2 = -7

and    -9 x 2 = -18

                          (x - 9) (x + 2) = 0

                          x₁  - 9 = 0               x₂ + 2 = 0

                         x₁ = 9                      x₂ = -2

Test

            (9)² - 7(9) - 18                      (-2)² - 7(-2) - 18

            81 - 63 - 18                          4 + 14 - 18

            81 - 81                                  18 - 18

            0                                           0

5 0
3 years ago
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