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3 years ago

In a right triangle, if sin 0 = 8/17 what is cos 0 explain?

Mathematics

1 answer:

Oliga [24]3 years ago

3 0

Answer:

We have sin² x + cos² x =1 for all real x.

Therefore, sin² x = 1 – cos² x = 1 – (8/17)² = 1 – 64/289 = 225/289 = (15/17)².

However, remember that if x² = a², then x can be +a or –a.

Therefore, sin x can be either –15/17 or +15/17.

Everyone but Anirban so far has forgotten the negative solution.

Step-by-step explanation:

Given that sinθ=817 and cosθ<0 , we have: cosθ=−√1−sin2θ. cosθ=−√1−(817)2. cosθ=−√1−64289.

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olga nikolaevna [1]

Answer:

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Step-by-step explanation:

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3 years ago

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olga_2 [115]

The measure of the angles are ∠A = 91°, ∠C = 89° and ∠D = 34°

Explanation:

Given that the quadrilateral ABCD is inscribed in a circle.

The given angles are ∠A = (2x + 3), ∠C = (2x + 1) and ∠D = (x - 10)

We need to determine the measures of the angles A, C and D

The value of x:

We know that, the opposite angles of a cyclic quadrilateral add up to 180°

Thus, we have,

$\angle A+\angle C=180^{\circ}$

Substituting the values, we have,

$2x+3+2x+1=180$

$4x+4=180$

$4x=176$

$x=44$

Thus, the value of x is 44.

Measure of ∠A:

Substituting $x=44$ in ∠A = (2x + 3)°, we get,

$\angle A=(2(44)+3)^{\circ}$

$=(88+3)^{\circ}$

$\angle A=91^{\circ}$

Thus, the measure of angle A is 91°.

Measure of ∠C :

Substituting $x=44$ in ∠C = (2x + 1)°, we get,

$\angle C=(2(44)+1)^{\circ}$

$=(88+1)^{\circ}$

$\angle C=89^{\circ}$

Thus, the measure of angle C is 89°.

Measure of ∠D :

Substituting $x=44$ in ∠D = (x - 10)°, we get,

$\angle D=(44-10)^{\circ}$

$\angle D=34^{\circ}$

Thus, the measure of angle D is 34°.

Hence, the measure of the angles are ∠A = 91°, ∠C = 89° and ∠D = 34°

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Black_prince [1.1K]

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Step-by-step explanation: you plug the function g(x) into the function f(x) .. substitue g(x) for the x in f(x)

G(x) = 1/x , so you plug that in the x of f(x) and get 1/x + 7

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