Answer:
distribution
Step-by-step explanation:
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\left[y \right] = \left[ 0\right][y]=[0] I hope helping with u
Answer:
Guess I'll agree with the other person.
Step-by-step explanation:
Answer:
The expected number of times is 4.
Step-by-step explanation:
Looking at the question, we see that this follows a geometric distribution because it is asking for the expected number of trials hat will bring about the FIRST SUCCESS. The probability of success is
Since it is a geometric distribution, we know that the expected value of a random variable X, E(X) that follows a geometric distribution is given as:
E(X) = 1/p where p is the probability of success.
Therefore, the expected number of times will be
E(X) = 1/(1/p) = 1/(1/4) = 4.
Hence, the expected number of times is 4.
I think for the question above, instead of 2 · 3^2 · 7 it is <span>2 · 3^2 · 5.
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Two numbers have prime factorizations of 2^2 • 3 • 5 and 2 • 3^2 • 5 (note 2 squared & 3 squared).
Now, to choose the GCF, you choose, for each base factor in either number, the least exponent-ed one; so the GCF needs a factor 2, a factor 3, and a factor 5. Thus the GCF is 30 (their product). [i.e,2 squared is not a common factor]
<span>To create the LCM, you choose, for each base factor in either number, the greatest exponented one. Thus, LCM needs a factor 2 squared, 3 squared, and 5, giving LCM = 4(9)(5) = 180.</span><span />
