For cos(2x) * (2cos(x) + 1) = 0, use the double angle identity for cos(2x), which is cos^2 x - sin^2 x = cos^2 x - (1-cos^2) = 2cos^2 x - 1.
So we have (2cos^2 x - 1)(2cos x + 1) = 0. So 2cos^2 x -1 = 0 or x = 0 and 2pi.
For 2sec^2 x + tan^2 x - 3 = 0, use the identity sec^2 x = tan^2 x + 1, so we have
2(tan^2 x + 1) + tan^2 x - 3 = 0 or
<span>2tan^2 x + tan^2 x - 1 = 0 or
</span>3 tan^2 x = 1.
So x = pi/2, pi/2 + pi = 3pi/2.
Answer:
6/8
4/10
9/12
9/20
9/20
Step-by-step explanation:
Answer:
x = -1
x = 3
Step-by-step explanation:
Add 1 to both sides:
Factor the left side:
Square root both sides:
Therefore:
Answer:
Area of Triangle Section= 76.5
Step-by-step explanation:
Area of a triangle= A=
A=
A=
A=76.5
