Given that the distance between two lines in the measurement instrument is 0.01m, the maximum error should be 0.01m/2 = 0.005 m.
If you do a good work, the real measure is 1.20m +/- 0.005m, this is between 1.195 and 1.205.
Answer:
w-2u-v
Step-by-step explanation:
Given are three vectors u, v and w.
In R^2 we treat first element as x coordinate and 2nd element as y coordinate.
Thus we mark (1,2) in the I quadrant, (-3,4) in II quadrant and (5,0) on positive x axis 5 units form the origin.
b) 
We have to find the values of a and b
]
Equate the corresponding terms

Divide II equation by 2 to get

Eliminate a
-5 = 5b: b=-1
a=-2
Hence
w = 2u-v
Answer:
<h2>16/18</h2>
Step-by-step explanation:
<h2>hopes this helps. Mark as brainlest plz!</h2>
X, x+1
x+x+1=131
2x+1=131
2x=131-1=130
x=130÷2 = 65
the integers are 65 and 66
-3/5 because you multiply 9/10 by -2/3