The five number summary for your class GPA is shown. Which box plot shows the class data?
2 answers:
Answer:
The 2nd box lot shows the class data. Also, the illustrated box plot with these marks is also shown in the attached figure.
Step-by-step explanation:
Given the box plot which shows the class data, we can indicate that,
- the minimum is 1.8,
- Q1 is 2.6,
- the median is 2.9,
- Q3 is 3.6, and
- the maximum is 4.0.
So, the 2nd box lot shows the class data.
Because,
- it indicates a minimum at 1.8
- Q1 (the first quartile, or the 25% mark) which is 2.6
- the median is 2.9
- Q3 (the third quartile, or the 75% mark) which is 3.6
- and the maximum is 4.0.
So, the illustrated box plot with these marks is also shown in the attached figure.
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Given that sequence 1.77, 1.92,2.07 is arithmetic sequence.
Using that we have to find 31st term.
To find that we can use nth term formula of arithmetic sequence which is given by:
where n is the number of term so n=31
t_n indicates nth term
a_1 is the first term so a_1=1.77
r is the common difference which is given by difference of consecutive terms
then r=1.92-1.77=0.15
Now plug these values into above formula
Hence final answer is 6.27.
The absolute value transforms a negative number into a positive number.
For example
Let z be a real number, then:
| z | It will always be a positive number.
This means that:
If z is a negative number, then:
| z | = -z
If z is a positive number, then:
| z | = z
This means that for the expression the expression y = 2 | x-3 | +5
When x-3 > 0 then:
| x-3 | = x-3
When x-3 < 0 then:
| x-3 | = - (x-3)
Then we can divide the expression into two functions f (x) and g (x).
f (x) = 2 (x-3) +5
f (x) = 2x-6 + 5
f (x) = 2x-1
For
g (x) = 2 (-x + 3) +5
g (x) = -2x + 6 + 5
g (x) -2x +11
For
(x-3) < 0
x < 3