Please someone help I need help been stuck on this for the longest

Mathematics

1 answer:

qaws [65]3 years ago

7 0

Answer:

a.) 16

b.) 8

Step-by-step explanation:

a. how much lower was the 6am temperature in Nome than in Wyoming

Essentially this question is asking us to find the difference of the temperatures of Nome and Wyoming at 6am

Temperature of Nome at 6am: -31

Temperature of Wyoming at 6am: -15

Difference between two temperatures: -31 - (-15)

The two negative signs cancel out and the sign changes to +

-31 + 15 = -16

The temperature in Nome was 16 degrees lower then in Wyoming

b. At noon the temperature of Boston had risen by 14 degrees. what was the temperature of boston at noon.

All we have to do for this one is add 14 to the temperature of Boston at 6am. ( This is because the question tells us the temperature has risen 14 degrees by noon )

-6 + 14 = 8

At noon the temperature would be 8 degrees in Boston.

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The function f(x) = x3 – 8x2 + x + 42 has zeros located at 7, –2, 3. Verify the zeros of f(x) and explain how you verified them.

xeze [42]

Answer:

zeros are {-2, 3, 7} as verified by graphing
end behavior: f(x) tends toward infinity with the same sign as x

Step-by-step explanation:

A graphing calculator makes finding or verifying the zeros of a polynomial function as simple as typing the function into the input box.

<h3>Zeros</h3>

The attachment shows the function zeros to be x ∈ {-2, 3, 7}, as required.

<h3>End behavior</h3>

The leading coefficient of this odd-degree polynomial is positive, so the value of f(x) tends toward infinity of the same sign as x when the magnitude of x tends toward infinity.

x → -∞; f(x) → -∞
x → ∞; f(x) → ∞

<em>Additional comment</em>

The function is entered in the graphing calculator input box in "Horner form," which is also a convenient form for hand-evaluation of the function.

We know the x^2 coefficient is the opposite of the sum of the zeros:

-(7 +(-2) +3) = -8 . . . . x^2 coefficient

And we know the constant is the opposite of the product of the zeros:

-(7)(-2)(3) = 42 . . . . . constant

These checks lend further confidence that the zeros are those given.

(The constant is the opposite of the product of zeros only for odd-degree polynomials. For even-degree polynomials. the constant is the product of zeros.)