Question

The function f(x) = -(x+4)^2+5 is written in vertex form and shows that the vertex of the graph of f is located at (-4,5)

Answer 1

There is only one value for x that makes $(x+4)^2=0$

Vertex form of an expression

Given the vertex form of the function expressed as:

$f(x) = -(x+4)^2+5$

If the function f(x) = 5

$5 = -(x+4)^2+5$

Subtract 5 from both sides

$5 = -(x+4)^2+5\\-(x+4)^2= 5-5\\-(x+4)^2=0$

Hence there is only one value for x that makes $(x+4)^2=0$

Learn more on vertex form here; brainly.com/question/525947