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victus00 [196]
2 years ago
9

The function f(x) = -(x+4)^2+5 is written in vertex form and shows that the vertex of the graph of f is located at (-4,5)

Mathematics
1 answer:
Varvara68 [4.7K]2 years ago
7 0

There is only one value for x that makes (x+4)^2=0

<h3>Vertex form of an expression</h3>

Given the vertex form of the function expressed as:

f(x) = -(x+4)^2+5

If the function f(x) = 5

5 = -(x+4)^2+5


Subtract 5 from both sides

5 = -(x+4)^2+5\\-(x+4)^2= 5-5\\-(x+4)^2=0\\

Hence there is only one value for x that makes (x+4)^2=0

Learn more on vertex form here; brainly.com/question/525947

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