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2 years ago

13

What are the zeros of the function of y=x^2-3x+2

2 answers:

lukranit [14]2 years ago

8 0

Answer:

(x-1)(x-2)

x=1, x=2

Step-by-step explanation:

natulia [17]2 years ago

3 0

Factor the function into (x-2)(x-1) and set each part equal to zero and solve for x.
x-2=0 x=2
x-1=0 x=1

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6/9 written two different ways

Rashid [163]

6/9 is equivalent to the fractions 60/90 and 600/900. The amount of zeros you add on does not matter as long as you do it to the top and bottom. The division sign cancels it out.

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3 years ago

If 5^2x = 1, what is the value of 'x' ?

SVETLANKA909090 [29]

Answer:

x = 0

Step-by-step explanation:

5^0 is 1, meaning that x must equal to 0 for the answer to be 5^0.

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2 years ago

Read 2 more answers

Let g be the function given by g(x)=limh→0sin(x h)−sinxh. What is the instantaneous rate of change of g with respect to x at x=π

lorasvet [3.4K]

The <em>instantaneous</em> rate of change of <em>g</em> with respect to <em>x</em> at <em>x = π/3</em> is <em>1/2</em>.

<h3>How to determine the instantaneous rate of change of a given function</h3>

The <em>instantaneous</em> rate of change at a given value of $x$ can be found by concept of derivative, which is described below:

$g(x) = \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}$

Where $h$ is the <em>difference</em> rate.

In this question we must find an expression for the <em>instantaneous</em> rate of change of $g$ if $f(x) = \sin x$ and evaluate the resulting expression for $x = \frac{\pi}{3}$ . Then, we have the following procedure below:

$g(x) = \lim_{h \to 0} \frac{\sin (x+h)-\sin x}{h}$

$g(x) = \lim_{h \to 0} \frac{\sin x\cdot \cos h +\sin h\cdot \cos x -\sin x}{h}$

$g(x) = \lim_{h \to 0} \frac{\sin h}{h}\cdot \lim_{h \to 0} \cos x$

$g(x) = \cos x$

Now we evaluate $g(x)$ for $x = \frac{\pi}{3}$ :

$g\left(\frac{\pi}{3} \right) = \cos \frac{\pi}{3} = \frac{1}{2}$

The <em>instantaneous</em> rate of change of <em>g</em> with respect to <em>x</em> at <em>x = π/3</em> is <em>1/2</em>. $\blacksquare$

To learn more on rates of change, we kindly invite to check this verified question: brainly.com/question/11606037

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2 years ago

a film canister in the shape of a cylinder has a height of 8 centimeters and a volume of the film canister. write an equation fo

uranmaximum [27]

Answer:

Part a) The equation for the volume of the film canister is

$32\pi=\pi r^{2}(8)$

Part b) The radius of the film canister is $2\ cm$

Step-by-step explanation:

<u><em>The complete question is</em></u>

A film canister in the shape of a cylinder has a height of 8 centimeters and a volume of 32π cubic centimeters.

a. Write an equation for the volume of the film canister.

b. What is the radius of the film canister?

Part a) Write an equation for the volume of the film canister

we know that

The volume of a cylinder is equal to

$V=\pi r^{2} h$

where

r is the radius of the circular base

h is the height of the cylinder

we have

$V=32\pi\ cm^3$

$h=8\ cm$

substitute

$32\pi=\pi r^{2}(8)$ ----> equation for the volume of the film canister

Part b) What is the radius of the film canister?

we have

$32\pi=\pi r^{2}(8)$

$32\pi=8\pi r^{2}$

Simplify

Divide by 8π both sides

$4=r^{2}$

square root both sides

$r=2\ cm$

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3 years ago

All of the scatter plots below display the data correctly, but which one of them displays the data best? By convention, a good s

Sav [38]

Answer

the third one

Step-by-step explanation:

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3 years ago