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poizon [28]
2 years ago
13

What are the zeros of the function of y=x^2-3x+2​

Mathematics
2 answers:
lukranit [14]2 years ago
8 0

Answer:

(x-1)(x-2)

x=1, x=2

Step-by-step explanation:

natulia [17]2 years ago
3 0
Factor the function into (x-2)(x-1) and set each part equal to zero and solve for x.
x-2=0 x=2
x-1=0 x=1
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Which type of rigid transformation is shown?
drek231 [11]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Take 9.5 gallons 6 1/3 poured out how much water is left in the tank
elena55 [62]
We can first convert 9.5 into fraction :

9.5= 9 1/2

Then we can use deduction to find out the answer:

9 1/2 - 6 1/3

=19/2 - 19/3

We change it to the same denominator:

=19×3/6 - 19×2/6

= 57/6 - 38/6

= 19/6

Therefore there are 19/6 or 3 1/6 gallons left in the tank.

Hope it helps!
4 0
3 years ago
Convert 5.100 × 10-3 to ordinary notation.<br> a.0.0005100<br> b.0.005100<br> c.510.0<br> d.5100
kondor19780726 [428]
5.100 x 10⁻³ = 5.100 x 0.001
                    = 0.005100      (shift the decimal point for 5 by 3 units left)

Alternatively, because 10⁻³ = 1/1000, therefore
5.100 x 10⁻³ = 5.1/1000

           0.0051
         ---------------
1000 | 5.100
           5000
           -------------
              1000
              1000
            
This yields the same result.

Answer: b. 0.005100
4 0
3 years ago
Copy the table below onto your paper. Complete it then write an equation that relates x and y.
IRISSAK [1]
The equation is y = x - 3. just subtract 3 to get all of the blank spots.
5 0
3 years ago
Pleases someone explain
Nikolay [14]

When you have a negative exponent, you move the base with the negative exponent to the other side of the fraction to make the exponent positive.

For example:

\frac{1}{y^{-2}} =\frac{y^2}{1} or y^2

2x^{-3} or \frac{2^1x^{-3}}{1} =\frac{2}{x^3}

\frac{1}{x^{-5}} =x^5

When a base with an exponent is divided by a base with an exponent, you subtract the exponents together. (But you can only combine the exponents when the bases are the same)

For example:

\frac{x^2}{y}   (can't combine because they have different bases of y and x)

\frac{x^5}{x^3} =x^{(5-3)}=x^2

\frac{2^2}{2} =2^{(2-1)}=2^1 = 2

When you multiply an exponent directly to a base with an exponent, you multiply the exponents together.

For example:

(x^2)^3=x^{(2*3)}=x^6

(y^2)^{10}=y^{(2*10)}=y^{20}

\frac{2e^0}{(e^{-3})^2}     First multiply the exponents together in the denominator

\frac{2e^0}{e^{(-3*2)}}= \frac{2e^0}{e^{-6}}        Now subtract the exponents together

2e^{(0-(-6))}  (two negative signs cancel each other out and become positive)

2e^{(0+6)}

2e^6

7 0
3 years ago
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