What are the zeros of the function of y=x^2-3x+2

Mathematics

2 answers:

lukranit [14]2 years ago

8 0

Answer:

(x-1)(x-2)

x=1, x=2

Step-by-step explanation:

natulia [17]2 years ago

3 0

Factor the function into (x-2)(x-1) and set each part equal to zero and solve for x.
x-2=0 x=2
x-1=0 x=1

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