What are the zeros of the function of y=x^2-3x+2
2 answers:
Answer:
(x-1)(x-2)
x=1, x=2
Step-by-step explanation:
Factor the function into (x-2)(x-1) and set each part equal to zero and solve for x.
x-2=0 x=2
x-1=0 x=1
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