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poizon [28]
2 years ago
13

What are the zeros of the function of y=x^2-3x+2​

Mathematics
2 answers:
lukranit [14]2 years ago
8 0

Answer:

(x-1)(x-2)

x=1, x=2

Step-by-step explanation:

natulia [17]2 years ago
3 0
Factor the function into (x-2)(x-1) and set each part equal to zero and solve for x.
x-2=0 x=2
x-1=0 x=1
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A cooler contains 5 bottle of lemonade, 4 bottles of water, and 3 bottles of juice. Each type is equally likely to be chosen. Ba
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I think the answer is 4

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What is 500 divided by 20
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The answer is 25 just use a calculator for that type of math
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The area of a rectangle invitation card is 3/10 square foot. Given that the length of the card is 4/5 foot, find its perimeter.
Leokris [45]
Area is length times width [A=(L)(W)], if we know that the area of the card is 3/10 and the length is 4/5 we can set up the equation 3/10=(4/5)(W) where W is width. Solve for W by deciding both sides by 4/5 and we get that W=3/8. To find the perimeter of the card were have to add up all the sides of the card so 3/8+3/8+4/5+4/5 which equals 47/20
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3 years ago
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Bob has 6 more times than quarters. He has $1.65 in all. How many coins of each type does he have?
mrs_skeptik [129]

Answer:

3 quarters 9 dimes

Step-by-step explanation:

D=dimes

D-6=quarters

0.10 D + 0.25(D-6) = 1.65

0.10D + 0.25D - 1.5 = 1.65

0.35D = 3.15

Dibide both sides by 0.35

D =9

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8 0
3 years ago
"A sample of 30 randomly selected oranges was taken from a large population, and their diameters were measured. The mean diamete
Yuki888 [10]

Answer:

The lower bound of the interval is 88.9mm and the upper bound is 93.1mm.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.85}{2} = 0.075

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.075 = 0.925, so z = 1.44

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.44*\frac{8}{\sqrt{30}} = 2.1

The lower end of the interval is the sample mean subtracted by M. So it is 91 - 2.1 = 88.9mm.

The upper end of the interval is the sample mean added to M. So it is 91 + 2.1 = 93.1 mm

The lower bound of the interval is 88.9mm and the upper bound is 93.1mm.

6 0
3 years ago
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