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Blababa [14]
3 years ago
9

I really need help on this question!!!

Mathematics
1 answer:
Effectus [21]3 years ago
6 0

A combination in this question, is combining 2 activities out of the 3.

The possible combinations are:

  • Parade and Roller Coaster.
  • Parade and Eat Ice Cream Cones.
  • Roller Coaster and Eat Ice Cream Cones.

If you need the opposite order:

  • Roller Coaster and Roller Coaster.
  • Roller Coaster and Eat Ice Cream Cones.
  • Eat Ice Cream Cones and Roller Coaster.

Hope This Helped! Good Luck!

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Help me... I did it again! I skipped the practice and study guides
Katyanochek1 [597]

Answer:

X = 1 3/4

Step-by-step explanation:

Hope this helps!

4 0
2 years ago
Which equation represents a circle with a center at (-3,5) and a radius of 6 units
Fittoniya [83]

Answer:

(x+3)^2 +(y-5)^2 = 36

Step-by-step explanation:

We can write the equation of a circle as

(x-h)^2 +(y-k)^2 = r^2  where (h,k) is the center and r is the radius

(x- -3)^2 +(y-5)^2 = 6^2  

(x+3)^2 +(y-5)^2 = 36

5 0
3 years ago
Solve the system of equations 2x-2y=-14 and 3x-y=-1 by combining the equations.
Veseljchak [2.6K]

The solution to the system of equations is x = 3 and y = 10

<h3>How to solve the equations?</h3>

The system is given as:

2x-2y=-14

3x-y=-1

Multiply (1) by 1 and (2) by 2

So, we have:

1(2x-2y=-14)

2(3x-y=-1 )

This gives

2x - 2y=-14

6x - 2y=-2

Subtract the equations

-4x = -12

Divide by -4

x = 3

Substitute x = 3 in 3x-y=-1

3(3)-y=-1

Evaluate

9 - y = -1

Solve for y

y = 10

Hence, the solution to the system of equations is x = 3 and y = 10

Read more about system of equations at:

brainly.com/question/12895249

#SPJ1

7 0
1 year ago
I don't understand it at alll someone please give me the answer
goldenfox [79]
I hope this helps you

7 0
3 years ago
Read 2 more answers
Please answer! I crossed out the ones you don’t have to complete.
Nina [5.8K]

Answer:

1. Rewriting the expression 5.a.b.b.5.c.a.b.5.b using exponents we get: \mathbf{5^3a^2b^4c}

5.  x^-6 = \frac{1}{x^6}

6. 5^{-3}.3^{-1}=\frac{1}{5^3.3^1}

7. a^{-3}b^0c^4=\frac{c^4}{a^3}

Step-by-step explanation:

Question 1:

We need to rewrite the expression using exponents

5.a.b.b.5.c.a.b.5.b

We will first combine the like terms

5.5.5.a.a.b.b.b.b.c

Now, if we have 5.5.5 we can write it in exponent as: =5^{1+1+1}=5^3

a.a as a^{1+1}=a^2

b.b.b.b as: b^{1+1+1+1}=b^4

So, our result will be:

5^3a^2b^4c

Rewriting the expression 5.a.b.b.5.c.a.b.5.b using exponents we get: \mathbf{5^3a^2b^4c}

Question:

Rewrite using positive exponent:

The rule used here will be: a^{-1}=\frac{1}{a^1} which states that if we need to make exponent positive, we will take it to the denominator.

Applying thee above rule for getting the answers:

5) x^{-6} = \frac{1}{x^6}

6) 5^{-3}.3^{-1}=\frac{1}{5^3.3^1}

7) a^{-3}b^0c^4=\frac{b^0c^4}{a^3}

We know that b^0=1 so, we get

a^{-3}b^0c^4=\frac{b^0c^4}{a^3}=\frac{c^4}{a^3}

4 0
3 years ago
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