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xxMikexx [17]
2 years ago
10

62=−3k+7(k+6)+4 solve for k

Mathematics
1 answer:
guajiro [1.7K]2 years ago
7 0

Step-by-step explanation:

62= -3k + 7k + 42 + 4

62 - 42 - 4 = 4k

16 = 4k

4 = k

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Sonia earned $2,100 at her uncle's orchard. If she worked for 70 weeks and earned the same amount of money each week, how much d
Drupady [299]

Answer:

30

Step-by-step explanation:

She earned 30$ a week(Brainlyest?)

7 0
2 years ago
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A figure is composed of a semicircle and a right triangle. Determine the area of the shaded region. Use 3.14 for π and round to
Aliun [14]

Answer:

A=9.5\ ft^2

Step-by-step explanation:

we know that

The area of the shaded region is equal to the area of triangle plus the area of semicircle

so

A=\frac{1}{2}bh+\frac{1}{2}\pi r^{2}

we have

b=4\ ft

Find the height of the right triangle applying the Pythagorean Theorem

5^2=h^2+4^2

h^2=9\\h=3\ ft

The radius of the semicircle is half the height of triangle

r=3/2=1.5\ ft

substitute in the formula

A=\frac{1}{2}(4)(3)+\frac{1}{2}(3.14)(1.5)^{2}

A=6+3.5=9.5\ ft^2

5 0
2 years ago
Read 2 more answers
Two numbers, a and b, are stored in one byte floating point notation using the least significant (rightmost) 3 bits for the expo
ehidna [41]

a=00110111 = 00110_2 \times 2^{111_2} = 6 \times 2^{-1} = 3


b=11011000 =  11011_2 \times 2^{000_2} = -(0100_2 + 1) =-(4+1)=-5


a+b=-2 = -1 \times 2^{001} = -2 \times 2^{0} = -4 \times 2^{-1} etc.


a+b=-2 = 11111001 = 11110000 = 11100111 = ...


Hard to select the correct answers without seeing the choices. Let's check a couple,


11111001 = -(00000+1) \times 2^{1} = -2 \quad\checkmark


11110000 = -(00001 + 1) \times 2^{0} = -2 \quad\checkmark


11100111 = -(00011 + 1) \times 2^{-1} = -4/2= -2 \quad\checkmark


4 0
3 years ago
Which of the following expressions is equivalent to a3 + b3?
lubasha [3.4K]
ANSWER
{a}^{3}  + {b}^{3} = (a + b)( {a}^{2 }  - ab +  {b}^{2} )


EXPLANATION

To find the expression that is equivalent to
{a}^{3}  + {b}^{3}
we must first expand
{(a + b)}^{3}
Then we rearrange to find the required expression.


So let's get started.


{(a + b)}^{3}  = (a + b) {(a + b)}^{2}

We expand the parenthesis on the right hand side to get,



{(a + b)}^{3}  = (a + b) ( {a}^{2} + 2ab +  {b}^{2}  )



We expand again to obtain,

{(a + b)}^{3}  =  {a}^{3}  + 3 {a}^{2}b + 3a {b}^{2}   +  {b}^{3}


Let us group the cubed terms on the right hand side to get,

{(a + b)}^{3}  =  {a}^{3}   +  {b}^{3}  + 3 {a}^{2}b + 3a {b}^{2}




{(a + b)}^{3}  =  {a}^{3}   +  {b}^{3}  + 3ab (a+ b)





We make the cubed terms the subject,

{(a + b)}^{3}  - 3ab (a+ b) =  {a}^{3}   +  {b}^{3}

We factor to get,


(a + b)({(a + b)}^{2}  - 3ab ) =  {a}^{3}   +  {b}^{3}


We expand the bracket on the left hand side to get,

(a + b)( {a}^{2}  + 2ab +  {b}^{2}   - 3ab ) =  {a}^{3}   +  {b}^{3}


We finally simplify to get,

(a + b)( {a}^{2}   - ab +  {b}^{2}  ) =  {a}^{3}   +  {b}^{3}
5 0
2 years ago
Read 2 more answers
Trigonometry:
Trava [24]

A. The approximate height of the building is 100 m

B. We can use the arc length formula to obtain an approximation of BC since angle A is small.

A.

The approximate height of the building is 100 m

To find the approximate height of the building, we consider the diagram.

From the diagram, we have that using trigonometry,

tanA = BC/AB

Now

  • A = 0.05 radians,
  • BC = height of building and
  • AB = 2 km = 2000 m
<h3 /><h3>Finding the value of BC</h3>

So, making BC subject of the formua, we have

BC = ABtanA

Substituting the values of the variables into the equation, we have

BC = ABtanA

BC =2000tan0.05

BC = 2000 × 0.05

BC = 100 m

So, the approximate height of the building is 100 m

B.

We can use the arc length formula to obtain an approximation of BC since angle A is small.

<h3 /><h3>Arc Length Formula</h3>

We know that the arc length formula L = rФ where

  • r = radius and
  • Ф = angle in radians
<h3 /><h3>The approximate height</h3>

Now BC = ABtanA

We know that Ф ≅ tanФ when Ф is small.

<h3 /><h3>The comparison</h3>

So, BC = AB × A which is the arc length formula with

  • L = BC,
  • r = AB and
  • Ф = A

So, we can use the arc length formula to obtain an approximation of BC since angle A is small.

Learn more about approximate height of building here:

brainly.com/question/3144976

7 0
2 years ago
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