Answer:
Step-by-step explanation:
the right choice is C
you use c^2=a^2+b^2
where the largest side is the hypotenuse
The solution depends on the value of

. To make things simple, assume

. The homogeneous part of the equation is

and has characteristic equation

which admits the characteristic solution

.
For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be

. Then

So you have


This means


and so the general solution would be
Answer:
(x -5)² + (y +4)² = 100 Should be the correct answer, hope this helps :)
Step-by-step explanation:
A circle centered at (h, k) with radius r will have equation ...
... (x -h)² + (y-k)² = r²
The point satisfies the equation for the circle. Filling in the given numbers, we have ...
... (x -5)² + (y+4)² = (-3-5)² + (2+4)² . . . . . . (h, k) = (5, -4), (x, y) = (-3, 2)
... (x -5)² + (y +4)² = 64 +36
Answer:
X=7 and y is y=40 length is 47
Step-by-step explanation:
<u>Answer-</u>
<em>The correct answer is</em>
<em>∠BDC and ∠AED are right angles</em>
<u>Solution-</u>
In the ΔCEA and ΔCDB,

As this common to both of the triangle.
If ∠BDC and ∠AED are right angles, then 
Now as
∠BCD = ∠ACE and ∠BDC = ∠AED,
∠DBC and ∠EAC will be same. (as sum of 3 angles in a triangle is 180°)
Then, ΔCEA ≈ ΔCDB
Therefore, additional information can be used to prove ΔCEA ≈ ΔCDB is ∠BDC and ∠AED are right angles.