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julia-pushkina [17]
3 years ago
5

I dont even know how to explain this, but please help

Mathematics
1 answer:
Inessa [10]3 years ago
5 0

Both <em>Px</em> + <em>Qy</em> = <em>R</em> and <em>Tx</em> + <em>Uy</em> = <em>V</em> have the same solution (2, 9), meaning the point (2, 9) lies on both lines such that <em>x</em> = 2 and <em>y</em> = 9 makes both equations true.

When you add these equations together, you get

(<em>Px</em> + <em>Qy</em>) + (<em>Tx</em> + <em>Uy</em>) = <em>R</em> + <em>V</em>

→   (<em>P</em> + <em>T</em> ) <em>x</em> + (<em>Q</em> + <em>U</em> ) <em>y</em> = <em>R</em> + <em>V</em>

so the first option is equivalent.

When you subtract the first equation from the second, you get

(<em>Tx</em> + <em>Uy</em>) - (<em>Px</em> + <em>Qy</em>) = <em>V</em> - <em>R</em>

→   (<em>T</em> - <em>P</em>) <em>x</em> + (<em>U</em> - <em>Q</em>) <em>y</em> = <em>V</em> - <em>R</em>

so the third option is also equivalent.

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<em />

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