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prohojiy [21]
2 years ago
13

Noah works at a museum and monitors a fish tank. The tank currently has 140

Mathematics
1 answer:
mixas84 [53]2 years ago
6 0

Answer:

B, E, G

Step-by-step explanation:

You might be interested in
A) What step I messed up on?
kicyunya [14]

Answer:

2.5 : 1

Step-by-step explanation:

(1) 150 : 60 ← divide both parts by 10

(2) 15 : 6 → ( not 100 : 60) ← divide both parts by 3

(3) 5 : 2 ← divide both parts by 2

(4) 2.5 : 1

5 0
2 years ago
A salesperson earns $200 a week plus a 4% commission on her sales. Which equation models the relationship between her sales in a
Oduvanchick [21]

For this case we have:

Let:

  • s: Profit from sales in a given week
  • e: Seller's weekly profit

e = 200 + c

Where "c" represents the commission.

The commission on sales can be observed with the application of a rule of three:

s ---------> 100%

c ---------> 4%

c =\frac{4(s)}{100}

c =\frac{4s}{100}

Thus, e is given by:

e = 200 +\frac{4s}{100}

Answer:

The equation that models the relationship between her sales in a given week, s, and her weekly earnings, e is:

e = 200 +\frac{4s}{100}

Option d


3 0
3 years ago
Read 2 more answers
How do I verify this identity? I know you should write sin2a as sin(a+a).
Kisachek [45]

SOLUTION

Given the question in the image, the following are the solution steps to verify the identity

STEP 1: Write the given identity

\sin 2\alpha=2\sin \alpha\cos \alpha

STEP 2: Verify the identity

\begin{gathered} \sin 2\alpha=2\sin \alpha\cos \alpha \\ \text{Consider the left hand side of the above trigonometry identity.} \\ \text{That is, }\sin 2\alpha\text{.} \\ \text{ Rewrite }\sin 2\alpha\text{ as }\sin (\alpha+a) \\ \text{ It is known that }\sin (a+b)=\sin (a)\cos b+\cos (a)\sin (b) \\ U\sin g\text{ this statement above, we have;} \\ \sin (\alpha+a)=\sin a\cos \alpha+\cos a\sin \alpha \\ \text{It is known that }xy+yx=xy+xy=2\times xy=2xy \\ U\sin g\text{ this statement above, we have;} \\ \sin a\cos \alpha+\cos a\sin \alpha=\sin a\cos \alpha+\sin \alpha\cos \alpha=2\times\sin \alpha\cos \alpha=2\sin \alpha\cos \alpha \\ \text{Hence, }\sin 2\alpha=2\sin \alpha\cos \alpha \end{gathered}

The verification of the identity is as seen above.

7 0
1 year ago
What is the answer for this equation-18-6k=(1+3k)
kompoz [17]
-18 - 6k = 1 + 3k
-6k - 3k = 1 + 18
-9k = 19
k = -19/9 or - 2 1/9
3 0
3 years ago
Mr. Ross washed
Viefleur [7K]

Answer:

the son. and 7/20

Step-by-step explanation:

you would ave the denominator to make them both 20 then the fractions would become 5/20 and 8/20 so it would be the son who washed the most. then add them together and get 13/20 so 7/20 laundry needs to be done

5 0
2 years ago
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