This is a ratio problem; the ratio of the length to width is constant (and therefore equal):
4 /6 = 15 / x
Now, with a ratio, we may do any allowable algebra operation: cross-multiply, invert both sides, multiply or divide both sides by the same amount, etc.
Let's cross-multiply:
4x = (15)(6)
x = 90/4
x = 22.5 in.
Answer:
Sorry nakalimutan ko
Step-by-step explanation:
Di koma search
Answer:
27
Step-by-step explanation:
13 + 23 = 36 x 3/4 = 27
Answer:
Step-by-step explanation:
![36-\left[100\div \:560-32\left(8\div \:4-1\right)\right]\\\\100\div \:560-32\left(8\div \:4-1\right)\\\\=100\div \:560-32\cdot \:1\\\\=\frac{100}{560}-32\cdot \:1\\\\=\frac{100}{560}-32\\\\=-\frac{891}{28}\\\\\\=36-\left(-\frac{891}{28}\right)\\\\36-\left(-\frac{891}{28}\right)\\\\=36+\frac{891}{28}\\\\\frac{36\cdot \:28}{28}+\frac{891}{28}\\\\\frac{36\cdot \:28+891}{28}\\\\=\frac{1899}{28}\\\\\\\frac{1899}{28}(1899\div28)=67\frac{23}{28}](https://tex.z-dn.net/?f=36-%5Cleft%5B100%5Cdiv%20%5C%3A560-32%5Cleft%288%5Cdiv%20%5C%3A4-1%5Cright%29%5Cright%5D%5C%5C%5C%5C100%5Cdiv%20%5C%3A560-32%5Cleft%288%5Cdiv%20%5C%3A4-1%5Cright%29%5C%5C%5C%5C%3D100%5Cdiv%20%5C%3A560-32%5Ccdot%20%5C%3A1%5C%5C%5C%5C%3D%5Cfrac%7B100%7D%7B560%7D-32%5Ccdot%20%5C%3A1%5C%5C%5C%5C%3D%5Cfrac%7B100%7D%7B560%7D-32%5C%5C%5C%5C%3D-%5Cfrac%7B891%7D%7B28%7D%5C%5C%5C%5C%5C%5C%3D36-%5Cleft%28-%5Cfrac%7B891%7D%7B28%7D%5Cright%29%5C%5C%5C%5C36-%5Cleft%28-%5Cfrac%7B891%7D%7B28%7D%5Cright%29%5C%5C%5C%5C%3D36%2B%5Cfrac%7B891%7D%7B28%7D%5C%5C%5C%5C%5Cfrac%7B36%5Ccdot%20%5C%3A28%7D%7B28%7D%2B%5Cfrac%7B891%7D%7B28%7D%5C%5C%5C%5C%5Cfrac%7B36%5Ccdot%20%5C%3A28%2B891%7D%7B28%7D%5C%5C%5C%5C%3D%5Cfrac%7B1899%7D%7B28%7D%5C%5C%5C%5C%5C%5C%5Cfrac%7B1899%7D%7B28%7D%281899%5Cdiv28%29%3D67%5Cfrac%7B23%7D%7B28%7D)
