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kozerog [31]
3 years ago
7

What is the value of x in the equation 2x- 1.3 = 5?

Mathematics
1 answer:
Basile [38]3 years ago
3 0
I hope this helps you

2x=5+1,3

2x=6,3


x=3,15
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Y = x2 – 3x + 10, find f(–2)
Ann [662]

Answer:Hello

I think it's 12

Step-by-step explanation:

Actually at first you should plus this tow parameters:2x-3x+10

and then you can put(-2)instead (x).

Now you find answer.

6 0
3 years ago
What is the length of Line segment B C, rounded to the nearest tenth? 13. 0 units 28. 8 units 31. 2 units 33. 8 units.
Len [333]

The length of the line segment BC is 31.2 units.

<h2>Given that</h2>

Triangle ABC is shown.

Angle ABC is a right angle.

An altitude is drawn from point B to point D on side AC to form a right angle.

The length of AD is 5 and the length of BD is 12.

<h3>We have to determine</h3>

What is the length of Line segment BC?

<h3>According to the question</h3>

The altitude of the triangle is given by;

\rm Altitude = \sqrt{xy}

Where x is DC and y is 5 units.

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The length DC is.

\rm Altitude = \sqrt{xy}\\&#10;\\&#10;12 = \sqrt{(DC) \times 5}\\&#10;\\&#10;\sqrt{DC } = \dfrac{12}{\sqrt{5}}\\&#10;\\&#10;

Squaring on both sides

\rm DC = \dfrac{144}{5}\\&#10;\\&#10;DC = 28.8

Considering right triangle BDC, use the Pythagorean theorem to find BC:

\rm BC^2 = DC^2+BD^2\\\\  BC^2 = (28.8)^2+(12)^2\\&#10;&#10;\\&#10;BC = \sqrt{829.44+144}\\&#10;\\&#10;BC = \sqrt{973.44}\\&#10;\\&#10;\rm BC = 31.2 \ units

Hence, the length of the line segment BC is 31.2 units.

To know more about Pythagoras Theorem click the link given below.

brainly.com/question/26252222

6 0
2 years ago
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klasskru [66]
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3 0
3 years ago
7x + 3y + 2x<br><br> Please help me
Pachacha [2.7K]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
A coin is tossed and a single 6 sided number cube is rolled. Find the probability of landing on the heads side of the coin and r
Delicious77 [7]

Answer:

The probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

Step-by-step explanation:

Given:

Coin is tossed and a single 6 sided number cube is rolled.

Let the event of tossing head be 'H' and event of rolling a 3 be 'R3'.

Now, we know that:

Probability of an event 'A' = Favorable outcomes of 'A' ÷ Total possible outcomes

Now, for tossing a coin, the total possible outcomes are head and tail. So, there are 2 possible outcomes.

So, probability of event 'H' is given as:

P(H)=\dfrac{n(H)}{n(S)}\\\\P(H)=\frac{1}{2}=0.5

Similarly, for rolling a 6 sided cube, the possible outcomes are numbers 1 to 6. So, the number of possible outcomes is, n(S)=6

Now, probability of rolling a 3 is given as:

P(R3)=\frac{n(R3)}{n(S)}\\\\P(R3)=\frac{1}{6}

Now, both the events 'H' and 'R3' occur together. So, the combined probability is the product of two individual probabilities as they are independent events. So,

P(H\ and\ R3)=P(H)\times P(R3)\\\\P(H\ and\ R3)=\frac{1}{2}\times \frac{1}{6}\\\\P(H\ and\ R3)=\frac{1}{12}=0.083

Note: Independent events are those events whose intersection is an empty set of events or the outcome of one event doesn't affect the outcome of the other event.

Therefore, the probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

4 0
4 years ago
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