First we have to find the diagonal of the card. We do this by using the Pythagoras theorem: A^2 = b^2 + c^2
= 6^2 + 4^2
=36 + 16
= 52
A^2= 52
Sqrt A^2 = sqrt 52
A = 7.2
Since the envelopes diagonal is 7.2 inches and the card’s diagonal is 8 inches and 7.2<8. Your answer is c)
Answer:
1 - True
2 - False
3 - False
4 - True
Step-by-step explanation:
N/A
$48
Here's how I found it ( just in case )
Answer:
<20,23>
Step-by-step explanation:
u= <4,5> and v= <0,-1>
2v = 2*<0,-1> = <0,-2>
5u = 5* <4,5> = <20,25>
2v+5u = <0,-2> + <20,25>
= <20,23>
i think the answer is 1/3 from 8x 6 =-46.7 i think