Answer:
y = (-4/5)x + 12/5
Step-by-step explanation:
Slope = (4-0)/(-2-3) = 4/-5 = -4/5
y = (-4/5)x + c
When x = 3, y = 0
0 = (-4/5)(3) + c
c = 12/5
y = (-4/5)x + 12/5
5y = -x + 12
5y + x = 12
<span>2n^2 - 7n - 3 = 0
a = 2
b = -7
c =-3
Then use the Quadratic formula:
x = [-b +-sqroot(b^2 -4*a*c)] / 2*a
</span>
Cos ( 390)
- 4 cot (-45)
Csc (60)
Hope this helps
4!= 4*3*2*1
Therefore,
2x0+x!= 0+x! = 0+4!
4*3*2*1 = 24 (#1)
Answer: below
Step-by-step explanation: Given f(x) =kxn where k is a constant, then f'(x) = nkx(n - 1)
Can you apply this principle to this problem, Let me know if you have any further questions about this problem. Thanks.
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