Answer:
Value of f (Parapedicular) = 7√6
Step-by-step explanation:
Given:
Given triangle is a right angle triangle
Value of base = 7√2
Angle made by base and hypotenuse = 60°
Find:
Value of f (Parapedicular)
Computation:
Using trigonometry application
Tanθ = Parapedicular / Base
Tan60 = Parapedicular / 7√2
√3 = Parapedicular / 7√2
Value of f (Parapedicular) = 7√2 x √3
Value of f (Parapedicular) = 7√6
You can use this equation to find the axis of symmetry or the vertex of the quadratic equation as long as it is in standard form
X= (-b/2a)
The answer is x=2
Two basic ways in which to do this problem:
1. Find and apply the LCD.
2. Convert all of the given numbers to their decimal form, to 2 or 3 places only.
Try #2 first:
5/6 = 0.83
4/5 = 0.80 is not between 5/6 and 1. Reject it.
4/7 = 0.57 Reject
6/7 = 0.86 This is between 5/6 and1. This is the answer.
A = -3 B = 39 +6 mo para makuha mo -6 nmn para sa a 3-6 is -3
Answer: (A) The image of JKL after a 90° counterclockwise about the origin is shown in figure 1. (B) The image of JKL after a reflection across the y-axis is shown in figure 2.
Explanation:
(A)
From the given figure it is noticed that the coordinate points are J(-4,1), K(-4,-2) and L(-3,-1).
If a shape rotate 90 degree counterclockwise about the origin, then,
Therefore, the vertex of imare are J'(-1,-4), K'(2,-4) and L'(1,-3). The graph is shown in figure (1).
(B)
If a figure reflect across the y-axis then,
Therefore, the vertex of imare are J''(4,1), K''(2,-4) and L''(3,-1). The graph is shown in figure (2).
