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nasty-shy [4]
3 years ago
6

Find the equation of the line in gradient form that passes through the points (3,0) and (-2,4)

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
4 0

Answer:

y = (-4/5)x + 12/5

Step-by-step explanation:

Slope = (4-0)/(-2-3) = 4/-5 = -4/5

y = (-4/5)x + c

When x = 3, y = 0

0 = (-4/5)(3) + c

c = 12/5

y = (-4/5)x + 12/5

5y = -x + 12

5y + x = 12

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Sergio039 [100]

Answer:

3/32

Step-by-step explanation:

One approach to doing this probelm is to evaluate all three functions F, G and H at x = 2:

F(2) = 2(2) - 1 = 3

G(2) = 3(2) + 2 = 8

H(2) = (2)^2 = 4

                                                           3/8

Then (F/G)(2) = (3/8), and (F/G/H) = -------- = 3/32

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8 0
3 years ago
Order the steps to solve the equation log(x^2-15)=log(2x) form 1 to 5
nasty-shy [4]

Answer:x=-5 and x=3

Step-by-step explanation:

log(x^2-15)=log(2x)

Cancel log at both sides we get

x^2-15=2x

Collect like terms

x^2-2x-15=0

x^2-3x+5x-15=0

x(x-3)+5(x-3)=0

(x+5)(x-3)=0

x+5=0 x-3=0

x=-5 x=3

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Answer: 9.1

Step-by-step explanation:

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