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3 years ago

Find the equation of the line in gradient form that passes through the points (3,0) and (-2,4)

Mathematics

1 answer:

Aleksandr-060686 [28]3 years ago

4 0

Answer:

y = (-4/5)x + 12/5

Step-by-step explanation:

Slope = (4-0)/(-2-3) = 4/-5 = -4/5

y = (-4/5)x + c

When x = 3, y = 0

0 = (-4/5)(3) + c

c = 12/5

y = (-4/5)x + 12/5

5y = -x + 12

5y + x = 12

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Is my answer correct?

Dmitry_Shevchenko [17]

Yes your answer is correct

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3 years ago

Which of the following values are in the range of the function graphed below? check all that apply

vodomira [7]

Answer:

Option D. 1

Option E. 1/2

Step-by-step explanation:

we know that

Looking at the graph

The domain is the interval ----> [-1,1]

$-1\leq x\leq 1$

The domain is all real numbers greater than or equal to -1 and less than or equal to 1

The range is the interval ----> [0,1]

$0\leq y\leq 1$

The range is all real numbers greater than or equal to 0 and less than or equal to 1

therefore

The values that are in the range are

1 and 1/2

5 0

3 years ago

Read 2 more answers

209 is what percent of 475?

professor190 [17]

Answer:

44%

Step-by-step explanation:

1) You divide 209 by 475

2) Take 0.44 and move the decimal over 1 place to make <u>44%</u>

8 0

3 years ago

What can you say about the sum of consecutive odd numbers starting with 1? that is, evaluate 1, 1c3, 1c3c5, 1c3c5c7, and so on,

Mice21 [21]

Let us add consecutive odd numbers and try to find any relationship.

1. 1

2. 1+3 = 4 ( square of 2 i.e $2^{2}$ )

3. 1+3+5 = 9 ( $3^{2}$ )

4. 1+3+5+7 = 16 ( $4^{2}$ )

5. 1+3+5+7+9 = 25 ( $5^{2}$ )

6. 1+3+5+7+9+11 = 36 ( $6^{2}$ )

7. 1+3+5+7+9+11+13 = 49 ( $7^{2}$ )

If we notice, the sum of the consecutive odd integers in each case is equal to the square of the place where it lies. For example, the sum of numbers in seventh place is equal to $7^{2}$ . The sum of the numbers in the fifth line is equal to $5^{2}$ .

4 0

3 years ago

Suppose given an isosceles triangle with a leg measuring 5 in. Two lines are drawn through some point on the base, each parallel

enot [183]

We have an isosceles triangle and 2 lines that are drawn through some ( any ) point on the base. The both lines are parallel to one of the legs. Then those lines with the legs of the triangle make a parallelogram. We can say that x and y are the sides of the parallelogram. Then: x + y = 5 in. And the perimeter of the parallelogram: P = 2 x + 2 y = 2 * ( x + y ).
P = 2 * 5 = 10 in. The rest is in the attachment.
Answer: The perimeter of the constructed parallelogram is 10 inches.

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5 0

4 years ago