The staff commute to work in different ways 2/5 drive, 4/15 catch the bus and 1/3 cycle
2 answers:
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Answer:
1 4/25 - 3/5, or 29/25 - 3/5, or
it doesn't really matter they all mean the same
Step-by-step explanation:
1 2/5m - 3/5(2/5m + 1)
multiply first
1 2/5m - 6/25m - 3/5
multiply 1 2/5 only so the denominator is 25 as we can't simplify 6/25, it's so we can add them together, we can't add 3/5 tho bc it's a different term so there's no need to multiply that.
1 10/25m - 6/25m - 3/5
add/subtract
1 4/25m - 3/5
Answer:
The equation to determine the length is .
The Length of the exercise mat is 16 feet.
Step-by-step explanation:
Given:
Perimeter of Rectangular mat =
Let the length of the mat be denoted by 'l'
And width be denoted by 'w'.
Also Given:
The length of the mat is twice the width of the mat.
So we can say that;
⇒ equation 1
Now we know that;
Perimeter of Rectangle is equal to twice the sum of length and width.
framing in equation form we get;
⇒ equation 2
Now Substituting equation 1 in equation 2 we get;
Applying Distributive property we get;
Hence, The equation to determine the length is .
On Solving the above equation we get;
Dividing both side by 6 we get;
Now Substituting the value of 'w' in equation 1 we get;
Hence The Length of the exercise mat is 16 feet.
We have that
A(-2,-4) B(8,1) <span>
let
M-------> </span><span>the coordinate that divides the directed line segment from A to B in the ratio of 2 to 3
we know that
A--------------M----------------------B
2 3
distance AM is equal to (2/5) AB
</span>distance MB is equal to (3/5) AB
<span>so
step 1
find the x coordinate of point M
Mx=Ax+(2/5)*dABx
where
Mx is the x coordinate of point M
Ax is the x coordinate of point A
dABx is the distance AB in the x coordinate
Ax=-2
dABx=(8+2)=10
</span>Mx=-2+(2/5)*10-----> Mx=2
step 2
find the y coordinate of point M
My=Ay+(2/5)*dABy
where
My is the y coordinate of point M
Ay is the y coordinate of point A
dABy is the distance AB in the y coordinate
Ay=-4
dABy=(1+4)=5
Mx=-4+(2/5)*5-----> My=-2
the coordinates of point M is (2,-2)
see the attached figure
A(-2,-4) B(8,1) <span>
let
M-------> </span><span>the coordinate that divides the directed line segment from A to B in the ratio of 2 to 3
we know that
A--------------M----------------------B
2 3
distance AM is equal to (2/5) AB
</span>distance MB is equal to (3/5) AB
<span>so
step 1
find the x coordinate of point M
Mx=Ax+(2/5)*dABx
where
Mx is the x coordinate of point M
Ax is the x coordinate of point A
dABx is the distance AB in the x coordinate
Ax=-2
dABx=(8+2)=10
</span>Mx=-2+(2/5)*10-----> Mx=2
step 2
find the y coordinate of point M
My=Ay+(2/5)*dABy
where
My is the y coordinate of point M
Ay is the y coordinate of point A
dABy is the distance AB in the y coordinate
Ay=-4
dABy=(1+4)=5
Mx=-4+(2/5)*5-----> My=-2
the coordinates of point M is (2,-2)
see the attached figure