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trapecia [35]
3 years ago
11

In a game of chance player spin the pointer of a spinner with six equal-sized sections. part A what is the sample space of the g

ame? ​
Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
5 0

Answer:

The sample space of the game is: S = {1, 2, 3, 4, 5, 6}.

Step-by-step explanation:

Sample space is a set of all possible outcomes of an experiment.

Consider a few example:

  • Consider the experiment of tossing a coin. The sample space of this experiment consists of only two outcomes, i.e. Heads (H) and Tails (T).
  • Consider the experiment of rolling a fair six-sided die. The sample space of this experiment consists of six outcomes, i.e. faces 1, 2, 3, 4, 5 and 6.
  • Consider the experiment of selecting a card from a pack of 52 cards. The sample space of this experiment consists of 52 distinct outcomes.

The probability of all the outcomes in a sample space always sum up to 1.

Thus, fulfilling the condition of a valid sample space.

In this case, a game is played by spinning a pointer of a spinner with six equal-sized sections.

So, the pointer has 6 possible sections to land.

The pointer lands on any of the 6 sections with same probability, i.e. \frac{1}{6}.

The sample space of the experiment is:

S = {1, 2, 3, 4, 5, 6}

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Answer:

X ____ 0 ______ 1 _______ 2

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Step-by-step explanation:

Given that :

Number of red balls = 4

Number of Blue balls = 3

Total number of balls = (4 + 3) = 7

Picking without replacement :

Number of picks = 2

1st pick is red :

Probability = (required outcome / Total possible outcomes)

USing combination formula :

nCr = n! / (n-r)! r!

Total possible outcome :

7C2 = 7! / 5!2! = 7*6 / 2 = 42 / 2 = 21

X = number of red

For red = 0;

P(x =0) = required outcome / Total possible outcomes

P(x = 0)

Required outcome : [4C0 * 3C2)]

P(x = 0) = [(4C0 * 3C2)] / 21 = (1*3)/21 = 3/21 = 1/7

P(x = 1)

Required outcome : [4C1 * 3C1)]

P(x = 1) = [(4C1 * 3C1)] / 21 = (4*3)/21 = 12/21 = 4/7

P(x = 2)

Required outcome : [4C2 * 3C0)]

P(x = 2) = [(4C2 * 3C0)] / 21 = (6*1)/21 = 6/21 = 2/7

Hence ;

X ____ 0 ______ 1 _______ 2

P(x) __ 1/7 _____ 4/7 _____ 2/7

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