Answer:chicken butt I need some points
Explanation:blm ✊✊✊✊ white lives don't
Answer:
5.00 grams of salt contain more particles than 5.0 grams of sugar
Explanation:
Salt = NaCl
Molar mass = 58.45 g/mol
Sugar = C₁₂H₂₂O₁₁
Molar mass = 342.3 g/mol
Sugar's molar mass is higher than salt.
So 1 mol of sugar weighs more than 1 mol of salt
But 5 grams of salt occupies more mole than 5 grams of sugar
5 grams of salt = 5g / 58.45 g/m = 0.085 moles
5 grams of sugar = 5g/ 342.3 g/m = 0.014 moles
In conclusion, we have more moles of salt in 5 grams; therefore there are more particles than in 5 g of sugar.
The standard formation equation for glucose C6H12O6(s) that corresponds to the standard enthalpy of formation or enthalpy change ΔH°f = -1273.3 kJ/mol is
C(s) + H2(g) + O2(g) → C6H12O6(s)
and the balanced chemical equation is
6C(s) + 6H2(g) + 3O2(g) → C6H12O6(s)
Using the equation for the standard enthalpy change of formation
ΔHoreaction = ∑ΔHof(products)−∑ΔHof(Reactants)
ΔHoreaction = ΔHfo[C6H12O6(s)] - {ΔHfo[C(s, graphite) + ΔHfo[H2(g)] + ΔHfo[O2(g)]}
C(s), H2(g), and O2(g) each have a standard enthalpy of formation equal to 0 since they are in their most stable forms:
ΔHoreaction = [1*-1273.3] - [(6*0) + (6*0) + (3*0)]
= -1273.3 - (0 + 0 + 0)
= -1273.3
Answer: -
The first step involves protonation of the carbonyl oxygen.
After protonation, the Alcohol oxygen now attacks the carbon of the carbonyl.
Thus a six membered ring is formed with 5 carbon atoms and 1 oxygen atom. The 1st position carbon atom has 2 OH groups.
One of these gets again protonated.
This leaves as water. With the loss of the H+, there results a carbonyl at 1 position.
Thus 5-hydroxypentanoic acid forms a lactone or 2-oxanone in presence of acid.
