According to the balanced equation of this reaction:
N2(g) + 3H2(g) ↔ 2NH3(g)
and when we have Kp = 4.51 x 10^-5 so, in the Kp equation we will substitute by the value of the P for each gas to compare the value with Kp = 4.51x10^-5
a) when we have 98 atm NH3, 45 atm N2, 55 atm H2 by substitution in Kp equation:
Kp= [p(NH3)]^2 / [p(N2)]*[p(H2)]^3 = [98]^2 / [45]*[55]^3
= 1.28x10^-3
So here the value is higher than the value of the given Kp.
so the reaction will go leftwards toward the reactants ( to reduce the value of Kp) to reach the equilibrium.
b) When 57 atm NH3, 143 atm N2, No H2 so like a) by substitution:
Kp = [57]^2 / [143] = 22.7
So the reaction will go leftwards toward the reactants to reduce the value of Kp to reach equilibrium.
c) when 13 atm NH3, 27 atm N2, 82 H2
Kp = [13]^2 / [27]*[82]^3 = 1.135 x 10^-5 So this value is lower than the Kp which is given.
so, the reaction will go towards the right toward the products to increase the value of Kp to reach the equilibrium.
Answer: 252.5 kPa
Explanation:
Given that:
initial volume of gas V1 = 5.00 L
initial pressure of gas P1 = 101 kPa.
new Volume V2 = 2.00 L
new pressure P2 = ?
Since, only pressure and volume are involved, apply the formula for Boyle's law
P1V1 = P2V2
101 kPa x 5.0L = P2 x 2.00L
505 = P2 x 2.00L
P2 = 505/2.00
P2 = 252.5 kPa
Thus, the new pressure of gas inside the piston is 252.5 kPa
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Answer:
100 °C, because it is the boiling point of water.
Explanation:
What is true in a saturated solution is that it cannot dissolve any more solute.
A saturated solution is a chemical solution that contains the highest concentration (maximum capacity) of a solute dissolved in the solvent. When additional solute is added to a saturated solution, it will not dissolve it but it may result in a solid precipitate or left as a gas. The saturation of a solution depends on various factors such as temperatures, pressure, and the chemical makeup of substances involved. Examples of saturated solutions include; carbonated water and mixture of sugar and vinegar.
