1.
Chance of finding a bug = 0.35
Chance of not finding a bug = 1 - 0.35 = 0.65
Probability of finding a bug in the first 3 programs =
Probability of not finding a bug in 2 out of the 3 and finding a bug in 1.:
0.65^2 * 0.35 = 0.147 = 0.15
Answer is A.
2.
Probability of heads = 0.50
Probability of tails = 0.50
Probability of heads on the fourth attempt = tails x tails x tails x heads = 0.5 x 0.5 x 0.5 x 0.5 = 0.0625
The answer is B.
62 / 15.5 = 92 / x
to find x cross multiply:-
62x = 15.5 * 92
x = (15.5*92) / 62
= 23
Answer:
The percentage of students who scored below 620 is 93.32%.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
Percentage of students who scored below 620:
This is the pvalue of Z when X = 620. So
has a pvalue of 0.9332
The percentage of students who scored below 620 is 93.32%.
The answer is <span>9.55 minutes
</span>
1. Turn 15 km into miles:
1 km = 0.621 mile
15 km = 15 * 0.621 mile = 9.315 miles
So, she ran 9.315 miles for 89 minutes
2. Calculate <span>how many minutes it took Jimena to run 1 mile during the race:
S</span>he ran 9.315 miles for 89 minutes.
She ran 1 mile for x minutes.
9.315 mi : 89 min = 1 mi : x
x = 89 min * 1 mi / 9.315 mi
x = 9.55 min
Answer:
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