This is a way to factoring trinomials (there exist different equivalent methods).
Multiply the trinomial but the term accompanying . This is the second line. Then, you could take the square of the 
, ant try to create a factor () () that will correspond to the expression in the second line. That is, we want 
In ? we put the corresponding numbers that, if we multiply them we will obtain 42, and if we add them we will obtain 13. This numbers are 6 and 7. Then, we have 
The last step is divide by the number that we multipy in the first step.
Answer: Total Volume = 15π + 18 π= 33π cubic mm
Step-by-step explanation:
What is the volume of the composite figure? Leave the answer in terms of π.
_33π mm3
We have a cone here conjoined to a semi-sphere.
so
Cone volume: C = (1/3)*(πr^2) * h
semi-sphere volume : V = (1/2)* (4/3) * (π * r^3)
r = 3 mm and h = 5mm
so C = (1/3)*(π (3)^2) * 5 = 15π cubic mm
V = (1/2)* (4/3) * (π * 3^3) = 18 π cubic mm
Total Volume = 15π + 18 π= 33π cubic mm
Answer:
Length equals 16 and Width equals 4
Step-by-step explanation:
First let us create an equation. We can use L and W for length and width.
If the length is 4 times the width, then we end up with: L = 4W
It then says, " If its length were diminished by 6 meters and its width were increased by 6 meters, it would be a square."
Since a square has an equal length and width then we end up with:
L - 6 = W + 6
Knowing this we can just substitute the first equation into the second one leaving us with: 4W - 6 = W + 6
We then remove a W from both sides so that the right side is left with a 6, and add 6 to both sides to remove the -6 from the left one.
This leaves us with 3W = 12
W = 4, and if we put that into our first equation, L = 4W, then Length equals 16, and Width equals 4. We can check this by putting it into the 2nd equation. 16 - 6 = 4 + 6.
Answer:
32.25
Step-by-step explanation:
Answer:
all 4 angles are congruent
Step-by-step explanation:
2 pairs of parallel sides.
4 right angles (90°).
Opposite sides are parallel and congruent.
All angles are congruent
