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3 years ago

Write the numerical expression. 6 times the sum of 12 and 8. Write your answer with no spaces.

Mathematics

1 answer:

Murljashka [212]3 years ago

7 0

Answer:

6(12+8)

Step-by-step explanation:

the word 'times' would indicate the multiplication of 2 numbers

the word 'sum' would indicate the addition of 2 numbers. in this case, 12 + 8 would be placed in parenthesis

hope this helps!! :)

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Which expressions are equivalent to 2(4f + 2g)?

andreyandreev [35.5K]

Answer:

For example, 8f + 4g is one of the most used expression

Another example is 4 (2f + g), is correct too

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2 years ago

31-62=152+2-6(3+21) i need the answer to this please help

Alex787 [66]

31-62=152+2-6(3+21)
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1 year ago

Q7Which statement is incorrect for the graph of thefunction y = -5 cosGcos( 3 (x – 3)) +62The period is 4.The amplitude is 3.The

guajiro [1.7K]

The given function is,

$y=-5\cos (\frac{\pi}{2}(x-3))+6$

The graph can be drawn as,

The period will be distance between two consequetive maximas,

$\text{Period}=1-(-3)=4$

Thus, period is correct.

The amplitude can be determined as,

$\begin{gathered} Amplitude=\frac{\max -\min }{2} \\ =\frac{11-1}{2} \\ =5 \end{gathered}$

Thus, amplitue is incorrect.

The range is,

$y\in\lbrack1,11\rbrack$

Thus, the range is correct.

The midline is,

$\begin{gathered} \text{midline}=\frac{\max +\min }{2} \\ =\frac{1+11}{2} \\ =6 \end{gathered}$

Thus, the midline is correct.

Thus, option (b) is the solution.

5 0

1 year ago

2p^2 -1 =7 <br> Would appreciate some help thank you

SIZIF [17.4K]

Answer: p = 2

Step-by-step explanation:

To solve this problem, you first have to add 1 to each side of the equation, leaving you with 2p^2 = 8. Then you divide by 2 on both sides leaving you with p^2 = 4. After that, you take the square root of both sides, and because 4 is a perfect square, you get p = 2 as your final answer.

5 0

3 years ago

Read 2 more answers

Findf '(3), where f(t) = u(t) · v(t), u(3) =1, 2, −2, u'(3) =8, 1, 4,andv(t) =t, t2, t3.

Reika [66]

Answer:

$f'(3)=100$

Step-by-step explanation:

Given:

$f(t)=u(t)\cdot v(t)\\u(3)=\left ( 1,2,-2 \right )\\u'\left ( 3 \right )=\left ( 8,1,4 \right )\\v(t)=\left ( t,t^{2},t^{3} \right )$

To find: $f'(3)$

Solution:

$v(t)=\left ( t,t^{2},t^{3} \right )$

At $t=3;$

$v(3)=(3,3^{2},3^{3} )=(3,9,27)$

Differentiate with respect to t

$v'(t)=\left ( 1,2t,3t^{2} \right )$

At $t=3;$

$v'(3)=\left ( 1,2(3),3(3)^{2} \right )=\left ( 1,6,27 \right )$

Using product rule, differentiate $f(t)=u(t)\cdot v(t)$ with respect to $t$

$f'(t)=u'(t)\cdot v(t)+u(t)\cdot v'(t)$

At $t=3;$

$f'(3)=u'(3)\cdot v(3)+u(3)\cdot v'(3)\\=\left ( 8,1,4 \right )\cdot \left ( 3,9,27 \right )+\left ( 1,2,-2 \right )\cdot \left ( 1,6,27 \right )\\=24+9+108+1+12-54\\=100$

7 0

3 years ago