Answer:
1,2, 1,203, 12,03, 12,3, 12,301
Step-by-step explanation:
1,2 → 1,200
1,203
12,3 → 12,300
12,301
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Answer:
Step-by-step explanation:
Distance between two points P(x1,y1) and Q(x2,y2) is given by: d(P, Q) = √ (x2 − x1)2 + (y2 − y1)2 {Distance formula} 2. Distance of a point P(x, y) from the origin is given by d(0,P) = √ x2 + y2.
The factor outside the parentheses is -1. Distribute using that factor.
2 - (4 - <em>x</em>) = 7<em>x</em> - 5<em>x</em>
<em />
-1 * 4 = -4 and -1 * -<em>x</em> = <em>x</em>
<em />
2 - 4 + <em>x</em> = 7<em>x</em> - 5<em>x</em>
Simplify.
-2 + <em>x</em> = 2<em>x</em>
<em>x</em> = 2<em>x</em> + 2
-<em>x</em> = 2
<em>x</em> = -2
<h3>
Answer:</h3>
<em>x</em> = -2
Answer:
The missing exponent is 5
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given the first two numbers of a sequence as 2, 6...
If it is an arithmetic difference, the common difference will be d = 6-2 = 4
Formula for calculating nth term of an ARITHMETIC sequence Tn = a+(n-1)d
a is the first term = 2
d is the common difference = 4
n is the number if terms
Substituting the given values in the formula.
Nth term Tn = 2+(n-1)4
Tn = 2+4n-4
Tn = 4n-4+2
Tn = 4n-2
2) If the sequence us a geometric sequence
Nth term of the sequence Tn = ar^(n-1)
r is the common ratio
r is gotten by the ratio of the terms I.e
r = T2/T1
r = 6/2
r = 3
Since a = 2
Tn = 2(3)^(n-1)
Hence the nth term of the geometric sequence is Tn = 2(3)^(n-1)
