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3 years ago

HELP ASAP PLEASEEEE!

Mathematics

1 answer:

Llana [10]3 years ago

4 0

Answer:

it is c

Step-by-step explanation:

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Please help! The question and answer choices are attached.

alexandr1967 [171]

The answer is B The function shown on the graph has a smaller rate of change but a higher starting point

6 0

2 years ago

Please provide the answer and explain

AfilCa [17]

Answer:

The answer is C. -2

Step-by-step explanation:

The formula for slope is referred to "rise over run". So in this case you rise 2 over one (2/1) That gives you 2. But since the line is going down is -2

7 0

3 years ago

Read 2 more answers

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago

Simplify each radical

const2013 [10]

Answer:

AECG

Step-by-step explanation:

sqrt(49) = 7

sqrt(a^2) = a

sqrt(b^2) = b

For every two variables you can take one out from under the root sign and thorough the other one away.

Answer: E

sqrt(36) = 6

sqrt(a^2) = a See comment for 1.

b must be left where it is. There is only 1 of them.

6asqrt(b)

Answer: A

3. sqrt(25) = 5

sqrt(b^2) = b

a must be left alone. There's only 1 of them.

5b sqrt(a)

answer: C

sqrt(81 a b)

sqrt(81) = 9

The variables must be left alone. There's only1 of them

9 sqrt(ab)

Answer G

8 0

2 years ago

My family and I are so confused on this! Help please!

-BARSIC- [3]

Answer:

10) Correct

11) Each row is equal to 12 when you multiply them together.

12) 24

Step-by-step explanation:

12) You multiply 4*3*2 to get the volume of 24, which is also the number of cubes needed to make the shape.

Please give brainliest if I helped! :)

3 0

2 years ago