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2 years ago

Describe in words a situation that can be represented by 7÷2

Mathematics

1 answer:

Gelneren [198K]2 years ago

6 0

Answer:

Example: There are 7 packs of candy, but only two people can share it equally.

Step-by-step explanation:

7/2= 3.5. If each person gets 3.5 bags, they both have an equal amount.

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A car requires 25 litres of petrol for covering a distance of 350 km how much petrol will be required by the car to cover a dist

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Perform the indicated operation. 9z^3/16xy . 4x/27z^3

ziro4ka [17]

Answer:

$\frac{1}{12y}$

Step-by-step explanation:

This is a multiplication problem.

We want to multiply $\frac{9z^3}{16xy}\cdot \frac{4x}{27z^3}$

We factor to get:

$\frac{9z^3}{4\times 4xy}\cdot \frac{4x}{9\times 3z^3}$

We now cancel out the common factors to get:

$\frac{1}{4\times y}\cdot \frac{1}{1\times 3}$

We now multiply the numerators and the denominators separately to get.

This simplifies to $\frac{1}{12y}$

Therefore the simplified expression is $\frac{1}{12y}$

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2 years ago

The product of two numbers is 10 times the value of 8 × 7. Which expression shows the two numbers?

Aleonysh [2.5K]

Answer: 7 x 80 i think

Step-by-step explanation:\

nothing

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2 years ago

In triangle ΔABC, ∠C is a right angle and CD is the height to

Zina [86]

Answer:

$m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha$

Step-by-step explanation:

The triangles are drawn below.

CD is perpendicular to AB as CD is height to AB.

Therefore, angles $m\angle CDB=m\angle CDA=90$ °

So, triangles ΔCBD and ΔCAD are right angled triangles.

Now, from the right angled triangle ΔABC,

$m\angle A+m\angle B =90\\\alpha+m\angle B=90\\m\angle B=90-\alpha$

From ΔCBD,

$m\angle CBD$ is same as $m\angle B$ .

So, $m\angle CBD=90-\alpha$

$m\angle BCD+m\angle BDC =90\\m\angle BCD+90-\alpha=90\\m\angle BCD=\alpha$

Now, from ΔCAD,

$m\angle CAD$ is same as $m\angle A$

So, $m\angle CAD=\alpha$

$m\angle CAD+m\angle ACD =90\\\alpha+m\angle ACD=90\\m\angle ACD=90-\alpha$

Hence, the unknown angles of both the triangles are:

$m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha$

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2 years ago

Describe in words a situation that can be represented by 7÷2​

Describe in words a situation that can be represented by 7÷2