Not sure but you can figure it out.
There are

ways of selecting two of the six blocks at random. The probability that one of them contains an error is

So

has probability mass function

These are the only two cases since there is only one error known to exist in the code; any two blocks of code chosen at random must either contain the error or not.
The expected value of finding an error is then
Answer:
8/17
Step-by-step explanation:
The correct and complete question is:
<em>Use △XYZ, in which ∠X is a right angle and tanY=8/15. What is the ratio for sinY?</em>
From definition:
tan(Y) = opposite/adjacent
From the graph and the question:
tan(Y) = XZ/XY = 8/15
Then:
XZ = 8 and XY = 15. Using pytaghorean theorem:
XZ² + XY² = YZ²
8² + 15² = YZ²
√289 = YZ
17 = YZ
From definition:
sin(Y) = opposite/hypotenuse
From the graph:
sin(Y) = XZ/YZ
sin(Y)= 8/17
Answer:
The probability that Bentely will be selected first = 0.046
Step-by-step explanation:
The person will be randomly selected, it is not stated that sex is considered in the selection.
The total number of people present at the party = 10 + 12 = 22
The probability that Bentely will be selected first = 1/22
The probability that Bentely will be selected first = 0.046
Yes 3/6 is greater than 0/6.
0/6 is equal to 0