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2 years ago

Write the expression in repeated multiplication form. Then write the expression as a power.

Mathematics

1 answer:

Sidana [21]2 years ago

8 0

Answer:

6^8

Step-by-step explanation:

(6^4)(6^4)

6^8

or something like that

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Tanya [424]

Answer:

$2.50$

Step-by-step explanation:

Given

$(x_1,y_1) = (-1,0.8)$

$(x_2,y_2) = (0,2)$

$(x_3,y_3) = (1,5)$

$(x_4,y_4) = (2,12.5)$

Required

The rate of change (b)

The above graph is represented as:

$y = ab^x$

For: $(x_2,y_2) = (0,2)$ ;

We have:

$y = ab^x$

$2 = a * b^0$

$2 = a *1$

$2 = a$

$a = 2$

For $(x_3,y_3) = (1,5)$ ,

We have:

$y = ab^x$

$5 = a * b^1$

$5 = a * b$

Substitute $a = 2$

$5 = 2 * b$

Divide by 2

$2.5 = b$

$b = 2.5$

<em>Hence, the rate of change is 2.50</em>

7 0

3 years ago

Twice the sum of a number and 8 is the same aa the difference of 3 and the number. Find the equation that could be used to find

Nezavi [6.7K]

Answer:

f your number is x, then the difference between that number and 8 would be x-8. Twice that is 2(x-8)

Three times the sum of the number and 3 would be 3(x+3). So, you get the equation:

2(x-8)=3(x+3)

2x-16=3x+9

x=-25

5 0

3 years ago

Express the given quantity as a single logarithm. ln x + a ln y − b ln z

professor190 [17]

The rules of logarithms tell you ...
• $\ln(a)+\ln(b)=\ln(a \cdot b)$
• $a \cdot \ln(b)=\ln(b^{a})$

$\ln(x)+a \cdot \ln(y)-b \cdot \ln(z)=\ln\left( \dfrac{x \cdot y^{a}}{z^{b}} \right)$

6 0

3 years ago

HELPPP ALSO SORRY FRO THE PIC

Eddi Din [679]

Answer:

The numbers below are all grater than one:

Step-by-step explanation:

ʕ•ᴥ•ʔ

8 0

3 years ago

66,681 rounded to the nearest ten thousand??

grandymaker [24]

Hey there! I'm happy to help!

This number is sixty six thousand six hundred eighty one. This means that our ten thousandths place is the first 6.

We look to the right place to see if it is 5 or bigger. It is also six.

Therefore we bump the ten thousands place up 1 to 7 and we make everything else 0, giving us 70,000.

Have a wonderful day! :D

7 0

3 years ago