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3 years ago

Write the expression in repeated multiplication form. Then write the expression as a power.

Mathematics

1 answer:

Sidana [21]3 years ago

8 0

Answer:

6^8

Step-by-step explanation:

(6^4)(6^4)

6^8

or something like that

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Find the measure of the missing angle

Vladimir79 [104]

Answer:

Step-by-step explanation:

82 + 58 + ? = 180

140 + ? = 180

? = 40

Have an amazing day!

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3 years ago

You deposit $100 in your bank account. The account earns 2% simple interest in 5 years. How much interest did you earn?

aniked [119]

Answer is $110.4080803 or $110.41 rounded

7 0

3 years ago

Paul’s Paints sells a 24-gallon case of paint for a total of $576, including tax. Stella’s Paints sells a 64-gallon case of pain

Ratling [72]

Find the unit rate, or cost of 1 gallon.

576/24=$24 per gallon
1664/64=$26 per gallon.

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There is a $2 difference.

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4 years ago

Simplify the expression.

Ivanshal [37]

Do you know how to change mixed fractions to improper fractions

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3 years ago

The population of a community is known to increase at a rate proportional to the number of people present at time t. The initial

qaws [65]

Answer:

Step-by-step explanation:

Let P be the population of the community

So the population of a community increase at a rate proportional to the number of people present at a time

That is

$\frac{dp}{dt} \propto p\\\\\frac{dp}{dt} =kp\\\\ [k \texttt {is constant}]\\\\\frac{dp}{dt} -kp =0$

Solve this equation we get

$p(t)=p_0e^{kt}---(1)$

where p is the present population

p₀ is the initial population

If the initial population as doubled in 5 years

that is time t = 5 years

We get

$2p_o=p_oe^{5k}\\\\e^{5k}=2$

Apply In on both side to get

$Ine^{5k}=In2\\\\5k=In2\\\\k=\frac{In2}{5} \\\\\therefore k=\frac{In2}{5}$

Substitute $k=\frac{In2}{5}$ in $p(t)=p_oe^{kt}$ to get

$\large \boxed {p(t)=p_oe^{\frac{In2}{5}t }}$

Given that population of a community is 9000 at 3 years

substitute t = 3 in ${p(t)=p_oe^{\frac{In2}{5}t }}$

$p(3)=p_oe^{3 (\frac{In2}{5}) }\\\\9000=p_oe^{3 (\frac{In2}{5}) }\\\\p_o=\frac{9000}{e^{3(\frac{In2}{5} )}} \\\\=5937.8$

<h3>Therefore, the initial population is 5937.8</h3>

7 0

3 years ago