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Zinaida [17]
3 years ago
8

The given line passes through the points (0, −3) and (2, 3).

Mathematics
1 answer:
Zolol [24]3 years ago
6 0
Y+2=(x+2) z+3=(y+3) a+4=(z+4)
You might be interested in
Trigonometry problem help please and thank you find angle wxz photo of problem is attached ​
Ksenya-84 [330]

Answer:

wxz = 25°

Step-by-step explanation:

way = 90

zxy = 65

So wxz = 25

Hope it helps you

5 0
3 years ago
Point B has coordinates ​(3​,1​). The​ x-coordinate of point A is negative 1. The distance between point A and point B is 5 unit
mina [271]

Answer:

Given in quesion:Point B (3,1) and point A is -1. Distance between A and B is 5 units.

Using distance formula for AB we obtain,

AB^2=(x2-x1)^2 + (y2-y1)^2

5^2=(3+1)^2 + (1-y)^2

25-16=(1-y)^2

9=(1-y)^2

1-y=3

y= -2

Therefore the possible co-ordinates of A are(-1,-2).This is your required answer.

3 0
3 years ago
Dan has a favorite number his number has the digit 8 in the ones place and the digit 5 in the tens place. what is Dan favorite n
Licemer1 [7]
The answer would be 85...;)
7 0
3 years ago
Read 2 more answers
How do you solve this?
sesenic [268]

Answer:

In general, we already know how to solve problems in a right triangle using the concept of trigonometry. Meanwhile, as we also know that the type of triangle is not only a right triangle, but there are isosceles, equilateral, or even random triangles. The question is how to solve the problems that exist in these triangles It is known that there is an arbitrary triangle with sides a, b, and c. The angle formed in front of side a is called angle α, the angle formed in front of side b is called angle β, and the angle formed in front of side c is called angle γ = 5

Step-by-step explanation:

x" + 5x + 6 = 0

(x + 2)(x + 3) = 0

x + 2 = 0

x = -2

x + 3 = 0

x = -3

#semogamembantu

5 0
3 years ago
Read 2 more answers
Dan says 3/5 is the |same as 3.5is he correct
Vladimir [108]
No. \frac{3}{5} is just division. You divide the top by the bottom.

3 / 5 = 0.6

So, 0.6 does not equal to 3.5.
6 0
3 years ago
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