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forsale [732]
3 years ago
5

Prove: An odd number cubed is an odd number. (2n + 1)^3 = [ ? ]n^3 + [ ? ]n^2 + [ ? ]n [ ? ](4n3 + 6n2 + 3n) + [ ? ] = an odd​

Mathematics
1 answer:
anastassius [24]3 years ago
6 0

Step-by-step explanation:

We know that odd * odd = odd

Thus odd*odd*odd = odd*odd = odd

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