Answer:
2.5 miles per hour
Step-by-step explanation:
ok, so we already know how long she walked in 1/2 hour and we need to find out how many miles in one full hour. So, i multiplied 1 1/4 times two to make up the one full hour and I got 2.5 miles. So the rate is 2.5 mph.
Answer:
f(-)=29/11
Step-by-step explanation:
Even though you don't want an explanation, I'll just tell you the basics lol.
So what you have to do, is plug in -7 for the x's.
it should look something like the equation below.

After that all you need to is just to subtract :)

Then after that all you need to do is just let the negatives cancel out each other so you should get:

Hope this helps!
Answer: 242 = 190 + 4t
Step-by-step explanation:
You know that the maximum capacity of the restaurant is 242 people, meaning that at most there can only be that many customers seated at that time. Normally, the equation would be 242 = 10b + 4t, but since you already know the number of booths, your work is cut in half, giving you 242 = 10(19) + 4t. The equation would be this because you have the capacity being equal to the number of tables x the number of people at each table and the number of booths x the number of people seated at each of them.
Answer:
you got this sound from the human body for you so much I was wondering what to say I'm sorry I'm not going anywhere you want to go get me on snap now I got you can do this is the best of
Answer:
∠JKH and ∠GHF
Step-by-step explanation:
<em>hey there,</em>
<em />
< Corresponding means "the angles which occupy the same relative position at each intersection where a straight line crosses two others. If the two lines are parallel, the corresponding angles are equal." The lines here are parallel so they are equal.
If you don't understand the meaning of the angles also, feel free to ask me about that too.
The two angles I listed are equal to equal to each other. When you look at the other options, they aren't equal, they might look less or more degrees.
If this won't be a multiple choice but short answer, try looking at angles that look similar and see if they would be able to match with the angle given. >
<u>Hope this helps! Feel free to ask anything else.</u>