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Tcecarenko [31]
3 years ago
7

I need an answer to this perplexing math problem! 6-8 (8+27)=?

Mathematics
2 answers:
zhenek [66]3 years ago
4 0

Answer:

-274

Step-by-step explanation:

Dmitry [639]3 years ago
3 0

Answer:

-274

Step-by-step explanation:

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The answer to this problem is 28.
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Consider the quadratic function that has x-intercepts of –1 and –7 and passes through the point (–2, –20). What is the value of
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-2+20 is 1 10 + 8 in the factored form
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To my knowledge, the answer should be there is no difference since I found the sum, however the answer is something else,
olga nikolaevna [1]
In the first series, the summation applies to the whole (2n+3) inside
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3 years ago
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solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. x-2y+
Alekssandra [29.7K]

Answer:

x = -5, y = -6, z = -3

Step-by-step explanation:

Given the system of three equations:

\left\{\begin{array}{l}x-2y+3z=-2\\6x+2y+2z=-48\\x+4y+3z=-38\end{array}\right.

Write the augmented matrix for the system of equations

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)

Find the reduced row-echelon form of the augmented matrix for the system of equations:

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)\sim \left(\begin{array}{ccccc}1&-2&3&|&-2\\0&-14&16&|&36\\0&-6&0&|&36\end{array}\right)\sim \left(\begin{array}{ccccc}1&3&-2&|&-2\\0&16&-14&|&36\\0&0&-6&|&36\end{array}\right)

Thus, the system of three equations is

\left\{\begin{array}{r}x+3z-2y=-2\\16z-14y=36\\-6y=36\end{array}\right.

From the last equation:

y=-6

Substitute it into the second equation:

16z-14\cdot (-6)=36\\ \\16z=36-84\\ \\16z=-48\\ \\z=-3

Substitute y = -6 and z = -3 into the first equation:

x+3\cdot (-3)-2\cdot (-6)=-2\\ \\x=-2+9-12\\ \\x=-5

7 0
4 years ago
What’s five multiplied my seven?
jeyben [28]

Answer:

35 is the answer

Step-by-step explanation:

it just is yeyeye

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