Answer:
Point A, B, and C are collinear points.
Step-by-step explanation:
When points lie on one line, meaning all of the points are on the same line --> this is known as collinear points.
Answer: i - 60

the two fives are supposed to be up y but i dont know how to put them
Step-by-step explanation:
Answer:
300 Square feet
Step-by-step explanation:
Susan built a rectangular fence around her swimming pool.
Length=15ft
Width(or Breadth)=10ft
Height=6ft
To solve this, picture a cuboid with the top and bottom open, that is the key to finding the Surface Area of the Fence.
Surface Area of a Cuboid= 2(LW+LH+WH)
However since the top and bottom are open, the Surface Area becomes
Surface Area of the fence= 2(LW+WH)
=2((15X6)+(10X6)
=2(90+60)=2 X 150 =300
Susan uses 300 Square feet to build her fence.
Answer:

Step-by-step explanation:
Hi there!
Slope-intercept form:
where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)
<u>1) Determine the slope</u>
where the two given points are
and 
Plug in the given points (-1, 4) and (0, 2)

Therefore, the slope of the line is -2. Plug this into
:

<u>2) Determine the y-intercept</u>

Recall that the y-intercept is the value of y when the line crosses the y-axis, meaning that the y-intercept occurs when x is equal to 0.
One of the given points is (0,2). Notice how y=2 when x=0. Therefore, the y-intercept of the line is 2.
Plug this back into the equation:

I hope this helps!
Answer:
In First method : counting up, counting back on a number line,
If we want the quotient after dividing the number by 5 then we count how many 5 we get from 0 to the dividend.
For example : 
Since, from 0 to 30 there are six 5's obtained. ( because 5 × 6 = 30 )
Thus, 
In Second Method : dividing by 10, and then doubling the quotient.
First we divide the number by 10 then multiply the quotient by 2.
For Example: 
Since, 

Thus, 
Now, when we compare the above methods then we conclude that for the smaller numbers first method is appropriate because for small numbers we can easily count total 5's from 0. While for large numbers Second method is appropriate because it is hard to count the total 5's for the large number.