First answer (x=-2)
...
(2)[(-2)^2]+6-20
2(4)+6-20
8+6-20
14-20
<em>-6 (answer)
</em><em>
</em><em />Second answer (x=5)
...
(2)[(-5)^2]+6-20
2(25)+6-20
50+6-20
56-20
<em>36 (answer)
</em>Hope this helps!
Given:
In a two-digit number, the tens digit is 5 less than the units digit.
The number itself is five more than three times the sum of its digits.
To find:
The number.
Solution:
Let the two digit number is ab. So,

Tens digit is 5 less than the units digit.
...(i)
The number itself is five more than three times the sum of its digits.



...(ii)
Using (i) and (ii), we get





Putting b=8 in (i), we get


Therefore, the required number is 38.
Answer:
1] x=4.21
2] 52.5
3] 3.82
4] 38.73
5] 32.005
6] 31.21
Step-by-step explanation:
So df = 8 so then 2x-6=8 which means that x is 7
1st integer: x
2nd integer: x+1
Add them up: 2x+1= 145145
2x= 145146
x=72,573
Answer;
1st integer: 72573
2nd integer; 72,574
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