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3 years ago

What is the answer ?

Mathematics

2 answers:

Helga [31]3 years ago

5 0

Answer:

I think the answer would be -8

DedPeter [7]3 years ago

4 0

I believe the answer is -6

You might be interested in

What is the quotient of 109.2 / 60

pogonyaev

Answer:

1.82

Step-by-step explanation:

$\frac{7 x 13}{2 x 5^{2} }$ = 1 $\frac{41}{50}$ = 1.82

5 0

2 years ago

What is the measure of SQ? 1. 95 2. 190 3. 265 4. 360

Vesnalui [34]

Answer:

The measure of arc SQ is 95° ⇒ (1)

Step-by-step explanation:

The measure of any circle is 360°

The measure of the subtended arc to an inscribed angle is twice the measure of this angle

In the given circle

∵ S lies on the circumference of the circle

∴ ∠QSR is an inscribed angle

∵ ∠QSR is subtended by arc QR

→ By using the 2nd rule above

∴ m arc QR = 2 × m∠QSR

∵ m∠QSR = 95°

∴ m arc QR = 2 × 95

∴ m arc QR = 190°

→ By using the 1st rule above

∵ m of the circle = m arc QR + m arc SQ + m arc SR

∵ m arc SR = 75° and m arc QR = 190°

→ Substitute them in the equation above

∴ 360 = 190 + m arc SQ + 75

→ Add the like term in the right side

∴ 360 = 265 + m arc QS

→ Subtract 265 from both sides

∵ 360 - 265 = 265 - 265 + m arc SQ

∴ 95° = m arc SQ

∴ The measure of arc SQ is 95°

7 0

3 years ago

Miguel's irrigation tank for his large garden held 45.5 gallons before he began to fill it at a rate of 17 gallons per minute. B

egoroff_w [7]

Answer:

Step-by-step explanation:

6 0

3 years ago

Evaluate 3(5 - 8) - 7

Salsk061 [2.6K]

Answer:

-16

Step-by-step explanation:

3*5=15

3*8=24

15-24= -9

-9-7=-16

7 0

3 years ago

Please help! ive been stuck on this for so long and i just keep getting frustrated can someone help walkme through this?

bagirrra123 [75]

For firework launched from height 100ft with initial velocity 150ft/sec, equation made is correct

(a) equation will be $h(t) = -16t^2+150t+100$

(b) Now we have to see when it will land. At land or ground level height h will be equal to 0. So simply plug 0 in h place in equation made in part (a)

$0 = -16t^2 + 150t + 100$

Now we have to solve this quadratic. We will use quadratic formula method to solve this equation.

$t = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$

a = -16, b = 150, c = 100.

Plugging these values in quadratic formula we get

$t = \frac{-150 \pm \sqrt{150^2-4(-16)(100)}}{2(-16)}$

$t = \frac{-150 \pm \sqrt{22500+6400}}{-32}$

$t = \frac{-150 \pm \sqrt{28900}}{-32}$

$t = \frac{-150+170}{-32} = \frac{20}{-32} = -0.625$

time cannot be negative so we will drop this answer

then $t = \frac{-150-170}{-32} = \frac{-320}{-32} = 10$

So 10 seconds is the answer for this

(c) To make table simply plug various value for t like t =0, 2, 4, 6, 8 till 10. Plug values in equation mad in part (a) and find h value for each t as shown

For t =0 seconds, $h = -16(0)^2+150(0)+100 = 100 feet$

For t =2 seconds, $h = -16(2)^2+150(2)+100 =336 feet$

For t =4 seconds, $h = -16(4)^2+150(4)+100 = 444 feet$

For t =6 seconds, $h = -16(6)^2+150(6)+100 = 424 feet$

For t =8 seconds, $h = -16(8)^2+150(8)+100 = 276 feet$

For t =10 seconds, $h = -16(10)^2+150(10)+100 = 0 feet$

(d) Axis of symmetry is given by formula

$x = \frac{-b}{2a}$

$t = \frac{-150}{2(-16)} =\frac{-150}{-32} = 4.6875$

t = 4.6875 is axis of symmetry line

(e) x-coordinate of vertex is again given by formula

$x = \frac{-b}{2a}$

so t = 4.6875

then to find y coordinate we will plug this value of t as 4.6875 in equation made in part (a)

For t =4.6875, $h = -16(4.6875)^2+150(4.6875)+100 = 451.563$

so vertex is at (4.6875, 451.563)

(f) As the firework is launched so in starting time is t=0, we cannot have time before t=0 (negative values) practically. Also we cannnot have firework going down into the ground so we cannot have h value negative physically.

6 0

3 years ago