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3 years ago

Question 2(Multiple Choice Worth 1 points)

1 answer:

3 0

X=4
(X+20)/2 = 3x
Multiply everything by 2 to cancel out the 2; therefore, (x+20)= 6x
Now solve for x,
20= 6x-x
20= 5x
Divide everything by 5 to solve for x,
20\5 = 5x/5
4=x

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A school is selling tickets to a drama performance. On the first day of ticket sales the school sold 3 adult tickets and 1 child

baherus [9]

Answer:

System of linear equations

$\left\{\begin{matrix} 3a+c=38 \\\\ 3a+2c=52 \end{matrix}\right.$

a: adult ticket price and c: child ticket price

Step-by-step explanation:

This system of equations can be used to find the price of the adult and child tickets.

We have two equations (one for each day) and two unknowns (adult ticket price and child ticket price).

Let a: adult ticket price and c: child ticket price,

we have for the first day that 3 adult tickets and 1 child ticket adds $38:

$3a+1c=38$

and for the second day we have that 2 adult tickets and 2 child tickets adds $52:

$3a+2c=52$

If we write this as a system of equations, we have:

$\left\{\begin{matrix} 3a+c=38 \\\\ 3a+2c=52 \end{matrix}\right.$

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3 years ago

Please answer plz

djyliett [7]

x + y = 3.36 --> the boys are splitting $3.36

x = 3y - .12 --> one boy received $.12 less than 3 times as much as the other

--> substitute the second equation for the x in the first equation

(3y - .12) + y = 3.36 --> combine like terms

4y - .12 = 3.36 --> add .12 to both sides of the equation

4y = 3.48 --> divide both sides by 4

y = .87

the other boy gets $0.87

substitute into x = 3y - 12

x = 3(.87) - .12

x = 2.61 - .12

x = 2.49

the first boy gets $2.49

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