All categories

3 years ago

Question 2(Multiple Choice Worth 1 points)

1 answer:

3 0

X=4
(X+20)/2 = 3x
Multiply everything by 2 to cancel out the 2; therefore, (x+20)= 6x
Now solve for x,
20= 6x-x
20= 5x
Divide everything by 5 to solve for x,
20\5 = 5x/5
4=x

You might be interested in

So in English in Quarter 1 i got a B. then for Quarter 2 i got a C+.

Assoli18 [71]

What's the percentages?? I need to know that first

8 0

3 years ago

Evaluate 17 + x<br> when x = 16

Vesnalui [34]

Answer: 17+ 16 = 33

Good luck !

3 0

3 years ago

A plane flying horizontally at an altitude of 1 mi and a speed of 470 mi/h passes directly over a radar station. Find the rate a

kiruha [24]

Answer:

407 mi/h

Step-by-step explanation:

Given:

Speed of plane (s) = 470 mi/h

Height of plane above radar station (h) = 1 mi

Let the distance of plane from station be 'D' at any time 't' and let 'x' be the horizontal distance traveled in time 't' by the plane.

Consider a right angled triangle representing the above scenario.

We can see that, the height 'h' remains fixed as the plane is flying horizontally.

Speed of the plane is nothing but the rate of change of horizontal distance of plane. So, $s=\frac{dx}{dt}=470\ mi/h$

Now, applying Pythagoras theorem to the triangle, we have:

$D^2=h^2+x^2\\\\D^2=1+x^2$

Differentiating with respect to time 't', we get:

$2D\frac{dD}{dt}=0+2x\frac{dx}{dt}\\\\\frac{dD}{dt}=\frac{x}{D}(s)$

Now, when the plane is 2 miles away from radar station, then D = 2 mi

Also, the horizontal distance traveled can be calculated using the value of 'D' in equation (1). This gives,

$2^2=1+x^2\\\\x^2=4-1\\\\x=\sqrt3=1.732\ mi$

Now, plug in all the given values and solve for $\frac{dD}{dt}$ . This gives,

$\frac{dD}{dt}=\frac{1.732\times 470}{2}=407.02\approx 407\ mi/h$

Therefore, the distance from the plane to the station is increasing at a rate of 407 mi/h.

6 0

3 years ago

B) Complete the frequency polygon

masya89 [10]

Could you explain this better. Maybe in a picture or better format?

7 0

3 years ago

Consider the statement "2 is a factor of n2 + 3n."

deff fn [24]

Answer:

The answer is the last one:

4 , 10 , 18 , (k + 1)² + 3(k + 1) and k² + 5k + 4

Step-by-step explanation:

∵ 2 is a factor of n² + 3n

∵ n = 1 ⇒ ∴ (1)² + 3(1) = 1 + 3 = 4 ⇒ 2 is a factor of 4

∵ n = 2 ⇒ ∴ (2)² + 3(2) = 4 + 6 = 10 ⇒ 2 is a factor of 10

∵ n = 3 ⇒ ∴ (3)² + 3(3) = 9 + 9 = 18 ⇒ 2 is a factor of 18

∵ n = k + 1 ⇒ ∴ (k + 1)² + 3(k + 1) ⇒ before the simplify

∵ n = k + 1 ⇒ ∴ k² + 2k + 1 + 3k + 3 = k² + 5k + 4 ⇒ after simplify

5 0

3 years ago