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LenKa [72]
3 years ago
11

A car was driving for 4 hours and covered 225 miles. A high-speed train is ten times as fast as this car. Find the train's speed

.
Mathematics
2 answers:
Lubov Fominskaja [6]3 years ago
5 0

Answer:

562.5 mph

Step-by-step explanation:

First, let's find how fast the car is going in miles per hour. We do this by dividing the miles by how many hours it took:

225/4 = 56.25

The car was going 56.25 mph

A high-speed train is ten times faster than this car so you multiply 56.25 by 10

(10)(56.25) = 562.5

The train's speed is 562.5 mph

<em>Hope this helps!</em>

<em>- Kay :)</em>

OLga [1]3 years ago
4 0

Answer:

The train covers 2250 miles in 4 hours compared to 225 miles covered in 4 hours by the car

Step-by-step explanation:

56.25 miles per hour - Car

562.50 miles per hour - Train

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A distribution of values is normal with a mean of 220 and a standard deviation of 13. From this distribution, you are drawing sa
Paraphin [41]

Answer:

The interval containing the middle-most 48% of sample means is between 218.59 to 221.41.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributied random variable X, with mean \mu and standard deviation \sigma, the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 220, \sigma = 13, n = 35, s = \frac{13}{\sqrt{35}} = 2.1974

Find the interval containing the middle-most 48% of sample means:

50 - 48/2 = 26th percentile to 50 + 48/2 = 74th percentile. So

74th percentile

value of X when Z has a pvalue of 0.74. So X when Z = 0.643.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

0.643 = \frac{X - 220}{2.1974}

X - 220 = 0.643*2.1974

X = 221.41

26th percentile

Value of X when Z has a pvalue of 0.26. So X when Z = -0.643

Z = \frac{X - \mu}{s}

-0.643 = \frac{X - 220}{2.1974}

X - 220 = -0.643*2.1974

X = 218.59

The interval containing the middle-most 48% of sample means is between 218.59 to 221.41.

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3 years ago
if you multiply the number by 2 and add 4, then result you get will be the same as three times the number decreased by 7.​
liraira [26]

Answer:

Step-by-step explanation:

Let the number be x,

2x+4 = 3x-7

Collect like terms

2x-3x= -4-7

-x =. -11

Multiply both sides by -1

x. =. 11

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3 years ago
There are 5 boys for every 6 girls.How many boys would there be if there were 36 girls?
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Answer:

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Step-by-step explanation:

If there are 5 for every 6, then you divide 36 by 6 and then you get 6

Once you get that, multiply 5 by 6 and get 30

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Answer:

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